4/12 is > or less than 7/10

Christine Wong has asked Dave and Mike to help her move into a new apartment on Sunday morning. She has asked them both in case

olga nikolaevna [1]

Answer:

(a) The probability that both Dave and Mike will show up is 0.25.

(b) The probability that at least one of them will show up is 0.75.

(c) The probability that neither Dave nor Mike will show up is 0.25.

Step-by-step explanation:

Denote the events as follows:

D = Dave will show up.

M = Mike will show up.

Given:

$P(D^{c})=0.55\\P(M^{c})=0.45$

It is provided that the events of Dave of Mike showing up are independent of each other.

(a)

Compute the probability that both Dave and Mike will show up as follows:

$P(D\cap M)=P(D)\times P (M)\\=[1-P(D^{c})]\times [1-P(M^{c})]\\=[1-0.55]\times[1-0.45]\\=0.2475\\\approx0.25$

Thus, the probability that both Dave and Mike will show up is 0.25.

(b)

Compute the probability that at least one of them will show up as follows:

P (At least one of them will show up) = 1 - P (Neither will show up)

$=1-P(D^{c}\cup M^{c})\\=P(D\cup M)\\=P(D)+P(M)-P(D\cap M)\\=[1-P(D^{c})]+[1-P(M^{c})]-P(D\cap M)\\=[1-0.55]+[1-0.45]-0.25\\=0.75$

Thus, the probability that at least one of them will show up is 0.75.

(c)

Compute the probability that neither Dave nor Mike will show up as follows:

$P(D^{c}\cup M^{c})=1-P(D\cup M)\\=1-P(D)-P(M)+P(D\cap M)\\=1-[1-P(D^{c})]-[1-P(M^{c})]+P(D\cap M)\\=1-[1-0.55]-[1-0.45]+0.25\\=0.25$

Thus, the probability that neither Dave nor Mike will show up is 0.25.

6 0

3 years ago

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A sentence for cofficient

sammy [17]

A coefficient is the (big) number in front of a number that tells you how many times you multiply the main number

4 0

3 years ago

Quantitative data

wariber [46]

The answer is A) measures things using quantities or numbers. Hope this helps!

8 0

3 years ago

What is the ratio of rise to run between the points (3, 4) and (–2, 0)?

mihalych1998 [28]

Answer:

○ B) ⅘

Step-by-step explanation:

Starting from the second endpoint, you go four blocks south over five blocks west [west and south are negatives], giving you ⅘.

I am joyous to assist you anytime.

4 0

3 years ago

1. (k+7)² =289 2. (2s-1)² =225 3. (x-4)² =169 please help me answer these :)

professor190 [17]

$(k+7)^2 =289\\
|k+7|=17\\
k+7=17\vee k+7=-17\\
k=10 \vee k=-24$

$(2s-1)^2 =225\\
|2s-1|=15\\
2s-1=15\vee 2s-1=-15\\
2s=16 \vee 2s=-14\\
s=8 \vee s=-7$

$(x-4)^2 =169\\
|x-4|=13\\
x-4=13 \vee x-4=-13\\
x=17 \vee x=-9$

6 0

3 years ago

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4/12 is > or less than 7/10​

4/12 is > or less than 7/10