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3 years ago

4. How many real-number solutions does the equation have?

1 answer:

5 0

2 solutions. This is because the parabola will cross the x axis twice. We know this because -5 means the vertex will be 5 units below the x axis. and the parabola opens upwards because the first coefficient is positive. Hope this helped :)

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What are the latitude and longitude coordinates of the entrance to the Mount Rushmore parking area?Latitude: 43.8753972, Longitu

Alborosie

Answer:

The answer is already in the question. The coordinates of the entrance to the Mount Rushmore parking area are given by latitude 43.8753972 and longitude -103.4523083.

Step-by-step explanation:

I believe the person asking the question wants some other detail that s/he did not state explicitly.

8 0

3 years ago

Help me from 6-9 (geometry)

elena55 [62]

Answer:

6) Two angles are called supplementary when their measures add up to 180 degrees. For example, two right angles are supplementary angles.

7) When the sum of two angles is equal to 90 degrees, they are called complementary angles. For example, 30 degrees and 60 degrees are complementary angles.

8) you have to plot the points on the graph and draw a line and label it with L at one point and M at another point.

9) x = 20

m < A = 65

m < B = 25

Step-by-step explanation:

3x + 5 + 2x - 15 = 90

3x + 2x + 5 - 15 = 90

5x - 10 = 90

5x - 10 + 10 = 90 + 10

5x = 100

5 / 5x = 100 / 5

x = 20

A = 3x + 5

A = 3(20) + 5

A = 60 + 5

A = 65

B = 2x - 15

B = 2(20) - 15

B = 40 - 15

B = 25

8 0

3 years ago

Pleaseeeee neeeddd helppp asappp

Rufina [12.5K]

ANSWER:

Segment TS is a Chord

If AR = 14 , then QS = 14 ×2 = 28

∆ATS is an Isosceles Triangle

HOPE THIS HELP YOU , FOR ANY QUESTION PLEASE ASK ME

7 0

2 years ago

WILL GIVE BRAINLIEST: What is the local minimum value of the function g(x)=x^4-5x^2+4? (Round answer to the nearest hundredth)

IrinaK [193]

Answer:

Step-by-step explanation:

you can find where the first derivative is 0 to find the critical points

g'(x) = ( x^4 -5x^2 +4)' = 4x³-10x

g'(x) =0, make y =0 to find find where g'(x) is 0

4x³-10x =0 , factor 2x

2x(2x²-5)= 0 , each factor must be 0

2x= 0, so x= 0

2x²-5 =0, so x = ±√5/2

we now have 3 critical points -√5/2, 0, and √5/2

make intervals (-∞, -√5/2), (-√5/2, 0) , (0, √5/2) and (√5/2, +∞)

pick a point to test on each interval: -2, -1, 1 and 2 for example, and

calculate g'(x) = 4x³-10x at those points

for x= -2 we have 4(-2)³-10(-2) = -12 , negative number, decrease

for x= -1 we have 4(-1)³-10(-1) =6, positive number, increase

for x= 1 we have 4(1)³-10(1) = -6, negative number, decrease

for x= 2 we have 4(2)³-10(2) = 12, positive number, increase

we went from a decrease to an increase on intervals (-∞, -√5/2), (-√5/2, 0) so x= - √5/2 ≈ -1.58 is a minimum

we went from a decrease to an increase on intervals (0, √5/2), (√5/2, +∞) so

x= √5/2 ≈ 1.58 is a minimum as well

4 0

3 years ago

The number of people arriving for treatment at an emergency room can be modeled by a Poisson process with a rate parameter of si

OverLord2011 [107]

Answer:

a) P(x=3)=0.089

b) P(x≥3)=0.938

c) 1.5 arrivals

Step-by-step explanation:

Let t be the time (in hours), then random variable X is the number of people arriving for treatment at an emergency room.

The variable X is modeled by a Poisson process with a rate parameter of λ=6.

The probability of exactly k arrivals in a particular hour can be written as:

$P(x=k)=\lambda^{k} \cdot e^{-\lambda}/k!\\\\P(x=k)=6^k\cdot e^{-6}/k!$

a) The probability that exactly 3 arrivals occur during a particular hour is:

$P(x=3)=6^{3} \cdot e^{-6}/3!=216*0.0025/6=0.089\\\\$

b) The probability that at least 3 people arrive during a particular hour is:

$P(x\geq3)=1-[P(x=0)+P(x=1)+P(x=2)]\\\\\\P(0)=6^{0} \cdot e^{-6}/0!=1*0.0025/1=0.002\\\\P(1)=6^{1} \cdot e^{-6}/1!=6*0.0025/1=0.015\\\\P(2)=6^{2} \cdot e^{-6}/2!=36*0.0025/2=0.045\\\\\\P(x\geq3)=1-[0.002+0.015+0.045]=1-0.062=0.938$

c) In this case, t=0.25, so we recalculate the parameter as:

$\lambda =r\cdot t=6\;h^{-1}\cdot 0.25 h=1.5$

The expected value for a Poisson distribution is equal to its parameter λ, so in this case we expect 1.5 arrivals in a period of 15 minutes.

$E(x)=\lambda=1.5$

3 0

3 years ago