Answer:
Number of 8th Graders = 360 - X
Step-by-step explanation:
As you can see this question is not complete and lacks the essential data. But we will try to create a mathematical expression to calculate the number of students on the A honor roll which are from 8th grade.
As we know:
Total number of students on the A honor roll = 360
We are asked to calculate, number of students from 8th grade on the A honor roll.
So, let's assume that "X" represents the all the students who are on the A honor roll except 8th grade.
Mathematical Expression:
Number of 8th Graders = Total number of students on the A honor roll - X
Number of 8th Graders = 360 - X
So, if you know the value of X, you can easily calculate the number of students which are from 8th grade on the A honor roll.
6x + 7(1-x) = -4(x-4)
6x + 7 - 7x = -4x + 16
-x + 7 = -4x + 16
-x + 4x = 16 - 7
3x = 9
x =9/3
x = 3
The answer will be
x=root 121
x=11
Answer:
A-3, B-4, C-1, D-2
Step-by-step explanation:
A:
- 5x-(3x+1)
- Expand, 5x-3x-1
- Combine like terms, 2x-1
B:
- 5x-(-3x-1)
- Expand, 5x+3x+1
- Combine like terms, 8x+1
C:
- -5x-(3x+1)
- Expand, -5x-3x-1
- Combine like terms, -8x-1
D:
- -5x-(-3x-1)
- Expand, -5x+3x+1
- Combine like terms, -2x+1
Answer:
a. V = (20-x) 
b . 1185.185
Step-by-step explanation:
Given that:
- The height: 20 - x (in )
- Let x be the length of a side of the base of the box (x>0)
a. Write a polynomial function in factored form modeling the volume V of the box.
As we know that, this is a rectangular box has a square base so the Volume of it is:
V = h *
<=> V = (20-x)
b. What is the maximum possible volume of the box?
To maximum the volume of it, we need to use first derivative of the volume.
<=> dV / Dx = -3 + 40x
Let dV / Dx = 0, we have:
-3 + 40x = 0
<=> x = 40/3
=>the height h = 20/3
So the maximum possible volume of the box is:
V = 20/3 * 40/3 *40/3
= 1185.185
