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Verizon [17]
3 years ago
9

Dwayne bought 5 yards of wrapping paper. How many inches of wrapping paper did he buy?

Mathematics
2 answers:
Igoryamba3 years ago
8 0
5 x 3 = 15 
15 x 12 = 180
Hope that helps! :)
saveliy_v [14]3 years ago
6 0

Answer:

<em>He bought 180 inches of wrapping paper.</em>

Step-by-step explanation:

<em>5 x 3 = 15 </em>

<em>15 x 12 = 180</em>

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Steven's Diner sold 60 milkshakes last week. ​25% of the milkshakes had whipped cream on top. ​ How many milkshakes with whipped
denis-greek [22]

Answer:

the answer is 15.

Step-by-step explanation:

you find the answer by turning 25% into 0.25 then you multiple it by 60, this results in 15.

3 0
3 years ago
Find the distance between the points (4, 6) and (2, -6). Round to the nearest tenth.
Deffense [45]

Answer:

The correct answer is B.12.2

Step-by-step explanation:

5 0
3 years ago
Factor completely and explain 4xy-14x+16y-56​
gulaghasi [49]

Answer:

2(2y−7)(x+4)

Step-by-step explanation:

Factor 4xy−14x+16y−56

4xy−14x+16y−56

=2(2y−7)(x+4)

5 0
3 years ago
If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that
Ivan

Answer:

\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

<u>Given</u><u> </u><u>:</u><u>-</u>

• \sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}

<u>To</u><u> </u><u>Prove</u><u> </u><u>:</u><u>-</u><u> </u>

•\sf\implies cos2A =\dfrac{\sqrt3}{2}

<u>Proof </u><u>:</u><u>-</u><u> </u>

We know that ,

\sf\implies cos2A = 1 - 2sin^2A

Therefore , here substituting the value of sinA , we have ,

\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2

Simplify the whole square ,

\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}

Add the numbers in numerator ,

\sf\implies cos2A =  1-2\times \dfrac{4-2\sqrt3}{8}

Multiply it by 2 ,

\sf\implies cos2A = 1 - \dfrac{ 4-2\sqrt3}{4}

Take out 2 common from the numerator ,

\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}

Simplify ,

\sf\implies cos2A =  1 -\dfrac{ 2-\sqrt3}{2}

Subtract the numbers ,

\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}

Simplify,

\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }

Hence Proved !

8 0
3 years ago
Determine the intercepts of the line.<br> y=5x-13<br><br> Y-Intercept ( , )<br> X-Intercept ( , )
Arte-miy333 [17]

Answer:

Y-intercept is (0, -13)

X-intercept is at (13/5, 0)

Step-by-step explanation:

When it's in this form, y = mx + b, you automatically know what the y-intercept is (b).

So the y-intercept is (0, -13)

To algebraically find this, you'd plug in a 0 for x, since the y intercept is when it crosses the y-axis, which is located at x = 0.

To find the x intercept, you'd do the opposite of the y-intercept, which is plugging in a 0 for y and solving for x. The x-axis is located at y = 0.

0 = 5x - 13

13 = 5x

x = 13/5

The x-intercept is at (13/5, 0)

I hope this helped!

3 0
3 years ago
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