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Akimi4 [234]
3 years ago
10

HELP FAST PLEASE HURRY I NEED IT TO BE RIGHT

Mathematics
1 answer:
drek231 [11]3 years ago
5 0

Answer:

{x + 4y = 8

{5x + 5y = 10

Step-by-step explanation:

Just add everything like it said, and you will arrive at your answer.

I am joyous to assist you anytime.

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Solve the following equation: 7/8 = -7
guajiro [1.7K]

Answer:

lets just say -8

Step-by-step explanation:

6 0
3 years ago
Write in point slope form an equation of the line that passes through the given point and has the given slope: (0,1); m= 2
sergey [27]

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\diamond\large\blue\textsf{\textbf{\underline{\underline{Question:-}}}}\diamond

         Write an equation for the line that passes through (0, 1) and has a slope of 2 (in point-slope form).

\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}\diamond

<u>Point-slope form</u>:-

      \sf{y-y_1=m(x-x_1)}

Substitute 1 for y₁, 2 for m, and 0 for x₁:-

\sf{y-1=2(x-0)}

So we conclude that Option B is correct.

<h3>Good luck.</h3>

            - - - - - -  - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

3 0
2 years ago
What is 3/4 divided by 7/12 as a fraction?
Yakvenalex [24]

Answer:

9/7

Step-by-step explanation:

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7 0
1 year ago
Read 2 more answers
HELP!!! First gets Top Answer!!!
Marta_Voda [28]
It is approximately -.4048

H=10^(-pH)

log H = -pH

pH=-logH => so it is affirmed that it is -.40

4 0
3 years ago
It’s a new semester! Students are grouped into three clubs, which each has 10, 4 and 5 students. In how many ways can teacher se
ozzi

Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.

So there are 3 clubs:

  • Club A, with 10 students.
  • Club B, with 4 students.
  • Club C, with 5 students.

The possible combinations of 2 students from different clubs are

  • Club A with club B
  • Club A with club C
  • Club B with club C.

The number of combinations for each of these is given by the product between the number of students in the club, so we get:

  • Club A with club B: 10*4 = 40
  • Club A with club C: 10*5 = 50
  • Club B with club C. 4*5 = 20

For a total of 40 + 50 + 20 = 110 different combinations.

This means that there are 110 different ways in which 2 students from different clubs can be selected.

If you want to learn more about combination and selections, you can read:

brainly.com/question/251701

6 0
2 years ago
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