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Neporo4naja [7]
3 years ago
10

Eight divided by √6-√3 i'm not sure how to divide with radicals in the denominator.

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
8 0
So just you need to rationalize the denominator so multiple top and bottom by conjugate so by sqrt6 +sqrt3

     8                           8(sqrt6 +sqrt3)                 8(sqrt6 +sqrt3)       
----------------- = ------------------------------------- = ----------------------- = 
sqrt6 - sqrt3     (sqrt6 -sqrt3)(sqrt6 +sqrt3)          6 -3                               


    8(sqrt6 +sqrt3)
= -----------------------
              3

hope this will help you 
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