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Bess [88]
3 years ago
6

How many four - digit numbers can be made from the numerals 7,6,5, and 3 4 12 24

Mathematics
2 answers:
Umnica [9.8K]3 years ago
8 0
12 if I'm not mistaken
andrezito [222]3 years ago
6 0

Answer:

12

Step-by-step explanation:

As you have 4 digist to create as many 4 digit numbers as you can you just have to think, how many starters do I have?

You have:

7

6

5

3

Those are how many you can start your number with, and then how many options of arrangements do I have for each one? and there are just three number to arrange in three different ways after that, it means that you have 4x3 ways to arrange those numerals to create 4 digit numbers.

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We have been given an expression \left(\dfrac {6}{17}\right)^{9x}. We are asked to find the value of A when rewrite our given expression as A^{x}.

To solve our given problem, we will use exponent properties.

Using exponent property a^{mn}=(a^m)^n, we can rewrite our given expression as:

\left(\dfrac {6}{17}\right)^{9x}=\left(\left(\dfrac {6}{17}\right)^9\right)^{x}

Now, we will compare our expression with  A^{x}.

Upon comparing \left(\left(\dfrac {6}{17}\right)^9\right)^{x} with A^{x}, we can see that A=\left(\dfrac {6}{17}\right)^9.

Therefore, the value of A is \left(\dfrac {6}{17}\right)^9.

We can further simplify \left(\dfrac {6}{17}\right)^9 as:

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