Answer:
the question is blurry, please resend it
Answer:
The 95% confidence interval for the true average strain is between 23.94% and 28.06%.
Step-by-step explanation:
We have the standard deviation of the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 13 - 1 = 12
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 12 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.18
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 26 - 2.06 = 23.94
The upper end of the interval is the sample mean added to M. So it is 26 + 2.06 = 28.06
The 95% confidence interval for the true average strain is between 23.94% and 28.06%.
1.) One hundred twenty-five and forty-seven thousandths
2.) 91/100.
3.) 2769/1000
4.) 0.074
5.) 3.705
6.) 75.69
7.) 0.162 is greater than 0.07
8.) 8.049 is greater than 8.0094
9.) 6
10.) 5.678
11.) 5.7
Answer:
6/8 = n/12
Step-by-step explanation:
hope it helps ;)))))))]))))
Answer:
125.6
Step-by-step explanation:
all you have to do is multiple the 3.14 with 40 cm to get 125.6 cm