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Verdich [7]
3 years ago
11

A box is x to inches high,(2x+3)inches wide, and (2x+5) of inches long. In terms of x, what is the volume (v) of the box?

Mathematics
1 answer:
Advocard [28]3 years ago
6 0

Answer:

The volume of the box is V=(4x^3+16x^2+15x)\ in^3

Step-by-step explanation:

we know that

The volume of the box is equal to

V=LWH

where

L is the length of the box in inches

W is the width of the box in inches

H is the height of the box in inches

we have

L=(2x+5)\ in\\W=(2x+3)\ in\\H=x\ in

substitute in the formula

V=(2x+5)(2x+3)x

V=(4x^2+6x+10x+15)(x)

V=(4x^2+16x+15)(x)

V=(4x^3+16x^2+15x)\ in^3

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Answer:

240

Step-by-step explanation:

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= 240 square inches

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A lot is 60 m by 38 m. A house 32 m by 9 m is built on the lot. How much area is left over?
OLEGan [10]

Answer:

1992

Step-by-step explanation:

60x38=2280

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Hope it helps!

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2 years ago
Logarithm 2. The alkalinity of a fluid (pH) can be modeled in terms of its hydrogen ion concentration (H^+,measured in moles/lit
makkiz [27]

ok. We are given the following equation:

ph=-\log (H)

Where:

\begin{gathered} P=\text{ alkalinity} \\ H=\text{ hydrogen ion concentration} \end{gathered}

Since we are asked to determine "H" we will solve for "H" in the equation. To do that we will first multiply both sides by -1:

-ph=\log (H)

Now, we will use the following property of logarithms:

\log _aB=c\rightarrow B=a^c

Applying the property and having into account that:

\log (H)=\log _{10}(H)

We get:

10^{-pH}=H

Now we substitute the given value of "pH = 4.5":

10^{-4.5}=H

Solving the operation:

0.000032=H

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