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Verdich [7]
3 years ago
11

A box is x to inches high,(2x+3)inches wide, and (2x+5) of inches long. In terms of x, what is the volume (v) of the box?

Mathematics
1 answer:
Advocard [28]3 years ago
6 0

Answer:

The volume of the box is V=(4x^3+16x^2+15x)\ in^3

Step-by-step explanation:

we know that

The volume of the box is equal to

V=LWH

where

L is the length of the box in inches

W is the width of the box in inches

H is the height of the box in inches

we have

L=(2x+5)\ in\\W=(2x+3)\ in\\H=x\ in

substitute in the formula

V=(2x+5)(2x+3)x

V=(4x^2+6x+10x+15)(x)

V=(4x^2+16x+15)(x)

V=(4x^3+16x^2+15x)\ in^3

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For this case we have a function of the form:
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3 years ago
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The constraint for the potential plant site 2 can be written as:
sdas [7]

Answer:

c. x21 + x22 + x23 less or equal than 2800 y2

Step-by-step explanation:

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4 0
3 years ago
PLEASE HELP ASAP
Lesechka [4]

Answer:

A. f and h

Step-by-step explanation:

For a linear function the First Differences of the y-values must be a constant. i.e. if we take the difference between any two consecutive y values or values of f(x) it should be the constant. For this rule to work, x values must change by the same number every time, which is true for all three given functions.

For function f:

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For function g:

The values of g(x) are: 8,4,16,32

We can see the difference among two consecutive values is not a constant. Since the first differences are not the same, this function is not a linear.

For function h:

The values of h(x) are: 28, 64, 100, 136

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5 0
3 years ago
Which system of equations is best represented by this graph?
lisabon 2012 [21]

Answer:

B what the other dude said

Step-by-step explanation:

5 0
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