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3 years ago

A box is x to inches high,(2x+3)inches wide, and (2x+5) of inches long. In terms of x, what is the volume (v) of the box?

Mathematics

1 answer:

Advocard [28]3 years ago

6 0

Answer:

The volume of the box is $V=(4x^3+16x^2+15x)\ in^3$

Step-by-step explanation:

we know that

The volume of the box is equal to

$V=LWH$

where

L is the length of the box in inches

W is the width of the box in inches

H is the height of the box in inches

we have

$L=(2x+5)\ in\\W=(2x+3)\ in\\H=x\ in$

substitute in the formula

$V=(2x+5)(2x+3)x$

$V=(4x^2+6x+10x+15)(x)$

$V=(4x^2+16x+15)(x)$

$V=(4x^3+16x^2+15x)\ in^3$

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The amount of time the husband and the wife spend on house work is measured for 15 women and their 15 husbands. For the wives th

dolphi86 [110]

Answer:

The value of the test statistic is z = -0.877.

Step-by-step explanation:

Testing the difference in mean time spent on housework between husbands and wives.

At the null hypothesis, we test if there is no difference, that is, the subtraction of the means is 0:

$H_0: \mu_H - \mu_W = 0$

At the alternate hypothesis, we test if there is a difference, that is, the subtraction of the means is different from 0.

$H_1: \mu_H - \mu_W \neq 0$

The test statistic is:

$z = \frac{X - \mu}{s}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, and s is the standard error.

0 is tested at the null hypothesis:

This means that $\mu = 0$

For the wives the mean was 7 hours/week and for the husbands the mean was 4.5 hours/week. The standard deviation of the differences in time spent on house work was 2.85.

This means that $X = 4.5 - 7 = -2.5, s = 2.85$

What is the value of the test statistic for testing the difference in mean time spent on housework between husbands and wives?

$z = \frac{X - \mu}{s}$

$z = \frac{-2.5 - 0}{2.85}$

$z = -0.877$

The value of the test statistic is z = -0.877.

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If ab = a, then b = A) 0 B) 1 C) a D) even

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Answer:

Step-by-step explanation:

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In your computation, approximate its value as 3.14.

andrey2020 [161]

Answer: d

Step-by-step explanation:

Find the area of the rectangle.

$A=l*w\\A=(15in)(12in)\\A=180in^2$

Find the area of the base of the semicircle.

$A=\pi r^2$

12 in would be the diameter, divide by 2 to get the radius.

$\frac{12}{2}=6$

Plug this into the formula.

$A=(3.14)(6)^2\\A=113.04in^2$

Since we do not have a full circle but a semi one instead, we must divide our result by 2.

$\frac{113.04}{2}=56.52in^2$

Add both areas.

180+56.52=236.52 $in^2$

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A metric unit of lenght that is equal to one tenth of a meter is

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It is decimeter :):):)

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