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3 years ago

A box is x to inches high,(2x+3)inches wide, and (2x+5) of inches long. In terms of x, what is the volume (v) of the box?

Mathematics

1 answer:

Advocard [28]3 years ago

6 0

Answer:

The volume of the box is $V=(4x^3+16x^2+15x)\ in^3$

Step-by-step explanation:

we know that

The volume of the box is equal to

$V=LWH$

where

L is the length of the box in inches

W is the width of the box in inches

H is the height of the box in inches

we have

$L=(2x+5)\ in\\W=(2x+3)\ in\\H=x\ in$

substitute in the formula

$V=(2x+5)(2x+3)x$

$V=(4x^2+6x+10x+15)(x)$

$V=(4x^2+16x+15)(x)$

$V=(4x^3+16x^2+15x)\ in^3$

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$\boxed{ \sf x=\dfrac{4\pm\sqrt{43}}{2}}$

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