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Kaylis [27]
3 years ago
15

What is the value of (-4) to the power of 4

Mathematics
1 answer:
alexira [117]3 years ago
3 0
(-4) to the power of 4 is equal to 256
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The length of the rectangular garden is 4 meters longer than the width. If the garden area is 60 square
rusak2 [61]

Step-by-step explanation:

Let x be the Width, and x+4 be the Length of the rectangle ; =>

Area = x*(x+4) = 60 ; =>

x^2 +4x - 60 = 0 ; Now solve the Quadratic equation using factoring to find x;

<h2>MARK ME BRAINLIEST!!</h2>
5 0
2 years ago
What is the volume of the prism that can be constructed from this net?<br><br><br> units3
kirza4 [7]
3×9=27
27×7=189 units³

I hope this helped!!!:)
4 0
3 years ago
Read 2 more answers
Is education related to programming preference when watching TV? From a poll of 80 television viewers, the following data have b
Luda [366]

Answer:

a) H0:  There is no association between level of education and TV station preference (Independence)

H1: There is association between level of education and TV station preference (No independence)

b) \chi^2 = \frac{(15-10)^2}{10}+\frac{(15-20)^2}{20}+\frac{(10-10)^2}{10}+\frac{(5-10)^2}{10}+\frac{(25-10)^2}{10}+\frac{(10-20)^2}{20} =33.75

c) \chi^2_{crit}=5.991

d) Since the p value is lower than the significance level we enough evidence to reject the null hypothesis at 5% of significance, and we can conclude that we have dependence between the two variables analyzed.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

                                  High school   Some College   Bachelor or higher  Total

Public Broadcasting       15                       15                          10                     40

Commercial stations      5                         25                         10                     40  

Total                                20                      40                          20                    80

We need to conduct a chi square test in order to check the following hypothesis:

Part a

H0:  There is no association between level of education and TV station preference (Independence)

H1: There is association between level of education and TV station preference (No independence)

The level os significance assumed for this case is \alpha=0.05

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

Part b

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{20*40}{80}=10

E_{2} =\frac{40*40}{80}=20

E_{3} =\frac{20*40}{80}=10

E_{4} =\frac{20*40}{80}=10

E_{5} =\frac{40*40}{80}=20

E_{6} =\frac{20*40}{80}=10

And the expected values are given by:

                                  High school   Some College   Bachelor or higher  Total

Public Broadcasting       10                       20                         10                     40

Commercial stations      10                        10                         20                     40  

Total                                20                      30                          30                    80

Part b

And now we can calculate the statistic:

\chi^2 = \frac{(15-10)^2}{10}+\frac{(15-20)^2}{20}+\frac{(10-10)^2}{10}+\frac{(5-10)^2}{10}+\frac{(25-10)^2}{10}+\frac{(10-20)^2}{20} =33.75

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(2-1)(3-1)=2

Part c

In order to find the critical value we need to look on the right tail of the chi square distribution with 2 degrees of freedom a value that accumulates 0.05 of the area. And this value is \chi^2_{crit}=5.991

Part d

And we can calculate the p value given by:

p_v = P(\chi^2_{3} >33.75)=2.23x10^{-7}

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(33.75,2,TRUE)"

Since the p value is lower than the significance level we enough evidence to reject the null hypothesis at 5% of significance, and we can conclude that we have dependence between the two variables analyzed.

7 0
3 years ago
This drawing would be a step in finding which point of concurrency in a triangle?
ad-work [718]

Answer:

A. Orthocenter

Step-by-step explanation:

In the given triangle, ΔWKS, the drawing shown the construction of a perpendicular line to the side KS that pass through the vertex <em>W </em>of ΔWKS. Therefore, the completed construction gives an altitude of the triangle ΔWKS

Repeating the same procedure from the vertex <em>S</em> to construct the perpendicular line (altitude) to the side WK, and from the vertex <em>K</em> the perpendicular line (altitude) to the side WS gives the three altitudes of the triangle

The point of intersection (the point of concurrency) of the three altitudes is the <em>orthocenter </em>of the triangle and the drawing would therefore be a step in finding the <em>orthocenter </em>of a triangle.

3 0
3 years ago
Write the number below (81) as a power with a base of 3 and a base of 9
likoan [24]

Answer:

base of 3 --> 3^4 (three to the fourth); base of 9 --> 9^2 (nine squared)

Step-by-step explanation:

<u>3 x 3</u> = 9 x <u>3</u> = 27 x <u>3</u> = 81 = 3^4

You multiply 3 by itself 4 times.

<u>9 x 9</u> = 81 = 9^2

You multiply 9 by itself 2 times.

5 0
1 year ago
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