Please help me need ASAPp

Can y’all help me with this question

nikitadnepr [17]

Answer:

I'm 100% sure it's 50.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

GE bisects DGF , m_ CGD= 2x - 2, m2 EGF= 37, m CGF = 7x + 2<br> mZCGD =<br> mZCGF =

stira [4]

Answer:

m<CGD = 26°

m<CGF = 100°

Step-by-step explanation:

m<CGD = 2x - 2

m<EGF = 37

m<CGF = 7x + 2

Since GE bisects <DGF, m<DGF = 2*m<EGF.

m<DGF = 2*37 = 74°

m<CGD + m<DGF = m<CGF (angle addition postulate)

(2x - 2) + (74) = (7x + 2)

Find the value of x using the equation above.

2x - 2 + 74 = 7x + 2

Collect like terms

2x + 72 = 7x + 2

-2 + 72 = 7x - 2x

70 = 5x

70/5 = 5x/5

14 = x

x = 14

m<CGD = 2x - 2

Plug in the value of x

m<CGD = 2(14) - 2 = 28 - 2

m<CGD = 26°

m<CGF = 7x + 2

m<CGF = 7(14) + 2 = 98 + 2

m<CGF = 100°

4 0

3 years ago

Write a quadratic function in standard form that passes through (-8, 0), (-2, 0), and (-6,8).

Pavlova-9 [17]

Answer:

-10xsquared-x+38

Step-by-step explanation:

so,

general eqn of quadratic equation is,

axsquared+bx+c=y

where,

x and y are exchanged by coordinates given in qn

1,64a-8b+c=0

2,4a-2b+c=0

or c=2b-4a

60a-6b=0

3,36a-6b+c=8

32a-4b=8

3 0

2 years ago

Ms. Hernandez has $100 to spend on parking and admission to the zoo. The parking will cost $7, and admission tickets will cost $

forsale [732]

Answer:

6

Step-by-step explanation:

15.50 x 6= 93 and 100-7=93 therefor its 6

3 0

3 years ago

The manager of a fast-food restaurant determines that the average time that her customers wait for service is 3.5 minutes.The ma

Lana71 [14]

Answer:

The advertisement should use 16 minutes.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

The manager of a fast-food restaurant determines that the average time that her customers wait for service is 3.5 minutes.

This means that $m = 3.5, \mu = \frac{1}{3.5} = 0.2857$

What number of minutes should the advertisement use?

The values of x for which:

$P(X > x) = 0.01$

So

$e^{-\mu x} = 0.01$

$e^{-0.2857x} = 0.01$

$\ln{e^{-0.2857x}} = \ln{0.01}$

$-0.2857x = \ln{0.01}$

$x = -\frac{\ln{0.01}}{0.2857}$

$x = 16.12$

Rounding to the nearest number, the advertisement should use 16 minutes.

5 0

3 years ago