0.0000075 = 7.5 x 10^6 --- Patients Blood
and it has to be between 0.0000006 and 0.000016
so <em>Yes</em> it is normal
Given:
Low tide height = 1 ft
High tide height = 5 ft
Tide period, T = 24 houts
Let the height of the tide be modeled by the expression
h(t) = K + A cos(bt)
Because the period is 24, therefore
b = (2π)/24 = π/12
That is,
h(t) = K + Acos[(πt)/12]
When r=0, h = 1, therefore
K + A cos(0) = 1, ot
K + A = 1 (1)
When t = 12 (half cycle), h = 5, therefore
K + A cos(π) = 5, or
K - A = 5 (2)
Add (1) and (2):
2K = 6
K = 3
From(1), obtain
A = 1 - 3 = - 2
Answer:
The required function is h(t) = 3 - 2 cos[(πt)/12]
The amplitude is 2 feet
The period is 24 hours
The midline of the function is h = 3 feet
A graph of the function is shown below.
Answer:
approx. 2.2 miles
Step-by-step explanation:
If we put 2/3 into a decimal, (.66) we then add it to the 6 miles, aprox. 6.6 miles. Divide 6.6 by 3,
and you're answer is 2.2.
Approx. 2.2 miles a day over a 3 day period.
Answer:
x = <1,5>
y = <-5,1>
Step-by-step explanation:
Let x, y be two vectors in 2D
defined as:
x = <a, b>
y = <c, d>
for x, y to be orthogonal, we know that their dot or scalar product must be zero so,
x . y = 0
<a, b> . <c, d> = 0
a*c + b*d = 0 ------ (A)
Now, consider any four values for a, b, c, and d respectively which satisfy the equation (A)
i.e. I chose (you can choose on your own choice):
a=1, b=5, c=-5, d=1
Verifying Equation (A):
(1)*(5) + (-5)*(1) =0
5 - 5 = 0
0 = 0 (True)
Therefore,
Our vectors x, y are:
x = <1, 5>
y = <-5, 1>
Answer:
identical in form or shape
Step-by-step explanation:
two triangles could be congruent as they both have 3 sides.