Answer:
$80,500
55,500 + 1,500t
Step-by-step explanation:
The question is an arithmetic progression series
Where,
a= first term
d= common difference
n= number of terms
a = $70,000
d= $1,500
n= 8 years
8th term = a + (n-1) d
= 70,000 + (8-1)1500
= 70,000 + 7(1500)
= 70,000 + 10,500
= $80,500
Jocelyn salary after 8 years is $80,500
Solve for when n = t
t th term = a + (n-1)d
= 70,000 + (t - 1)1500
= 70,000 + 1,500t - 1,500
= 55,500 + 1,500t
t th term = 55,500 + 1,500t
(4)^36
Multiply the exponent 6 by 6 to get the new exponent of 36
Answer:
and 
Step-by-step explanation:
We require 2 equations with the repeating numbers placed after the decimal point.
let x = 0.1212...... (1) ← multiply both sides by 10
100x = 12.1212.... (2)
subtract (1) from (2) thus eliminating the repeating numbers
99x = 12 ( divide both sides by 99 )
x =
=
← in simplest form
-------------------------------------------------------
let x = 0.037037....... (1) ← multiply both sides by 1000
1000x = 37.037037..... (2)
subtract (1) from (2) to eliminate the repeating numbers
999x = 37 ( divide both sides by 999 )
x =
=
← in simplest form
Answer:
X = -3/7
Step-by-step explanation:
The answer would be C. Median.