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3 years ago

The cosine of an angle is .28. Find the sine of the angle.

Mathematics

1 answer:

musickatia [10]3 years ago

5 0

The ARC cosine of .28 = 73.74 degrees
the sine of 73.74 degrees = .96

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A candy box measures 8.2 cm in diameter and 15 cm in height. How many 2 cm cubed pieces of candy can fit into the box?

Katarina [22]

60 2cm candy prices can fit because if you multiply 8.2 by 15 it equals a decimal and if you divide it by 2 that the nearest whole number you’ll get is 60, so the answer has to be 60.

8 0

2 years ago

An equation is shown below:

IrinaK [193]

5(2x - 8) + 15 = -15
-15 -15 subtract 15 from each side
5(2x - 8) = -30
÷5 ÷5 divide both sides by 5
2x - 8 = -6
+8 +8 add 8 to each side
2x=2
÷2 ÷2 divide both sides by 3
x = 1

Checking:
5(2(1)-8) + 15 = -15
5(-6) + 15 = -15
-30 + 15 = -15
-15 = -15 Correct! x=1

7 0

3 years ago

Read 2 more answers

Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

3 years ago

Which expression is equivalent to the square root of 1/8

irina1246 [14]

When you say "which," it sounds like it should be multiple choice. Anyways, here's the simplified form of $\sqrt{\frac{1}8}}$

$\sqrt{\frac{1}8}} = \frac{\sqrt{1}}{\sqrt{8}} = \frac{1}{\sqrt{8}} * \frac{\sqrt{8}}{\sqrt{8}}=\boxed{\frac{\sqrt{8}}8}$

(When simplifying fractions, you should <em>never</em> have a square root on the bottom. Multiply by the square root to cancel it out)

4 0

3 years ago

Can someone answer these pls

vazorg [7]

Answer:

x = -2

Step-by-step explanation:

hope this helps you

6 0

3 years ago

Read 2 more answers