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Karolina [17]
3 years ago
6

Simply as much as you can.

Mathematics
1 answer:
kenny6666 [7]3 years ago
3 0

Answer:

The answer to your question is: 6/5

Step-by-step explanation:

\frac{8(-4) - 16}{5(-8)}

\frac{-32 -16}{-40}

\frac{-48}{-40}

\frac{24}{20}

\frac{12}{10}\frac{6}{5}

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3x + x = 1044

4x = 1044 - divide both sides by four

x = 261

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A sequence of numbers a1, a2, a3, . . . is defined as follows: a1 = 3, a2 = 5, and every term in the sequence after a2 is the pr
Hoochie [10]
Since n>2 n 
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so a3=t 

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3 0
3 years ago
Please, I NEED HELP. Anyone?
olchik [2.2K]

Answer:  

<em>(a) The system that models the situation:   b+c= 280 and 0.14b+0.07c= 22.4</em>

<em>(b) David needs 40 pounds of bread flour and 240 pounds of cake flour.</em>

Step-by-step explanation:

The amount of flour mixture is 280 lb. that is 8% plain flour.

So, the amount of plain flour in the mixture will be:  (280*0.08)lb.= 22.4 lb.

The number of pounds of bread flour and cake flour needed to make the new mixture are b and c respectively.

<u>So, the first equation will be</u>:   b+c= 280 ...................................(1)

The bread flour has 14% plain flour and the cake flour has 7% plain flour.

Thus, the amount of plain flour in bread flour =0.14b lb. and the amount of plain flour in cake flour = 0.07c lb.

<u>So, the second equation will be</u>:   0.14b+0.07c= 22.4 ................................(2)


From equation (1), we will get:   b= 280-c

Now substituting this b= 280-c into equation (2) in place of b........

0.14(280-c)+0.07c= 22.4\\ \\ 39.2-0.14c+0.07c=22.4\\ \\ -0.07c=22.4-39.2\\ \\ -0.07c=-16.8\\ \\ c=\frac{-16.8}{-0.07}=240

Plugging this c=240 into equation (1), we will get.....

b+240=280\\ \\ b=280-240=40

So, David needs 40 pounds of bread flour and 240 pounds of cake flour.

7 0
3 years ago
If y varies directly with x and y = 5 when x = 4, find the value of y when x = -8
Ket [755]

Answer:

-10

Step-by-step explanation:

y : x

= 5 : 4

4z = -8

= -8 / 4 = -2 = z

y : x

= 5 * -2 : 4 * -2

= -10 : -8

7 0
3 years ago
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