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Yanka [14]
3 years ago
15

Given a polynomial and one of its factors bother main factors 9x^3 + 20x^2 - 68x - 16; (x+4)

Mathematics
1 answer:
icang [17]3 years ago
8 0

Answer:

9x+2 and x-2.

Step-by-step explanation:

Given the polynomial 9x^3 + 20x^2 - 68x - 16

If one of the factors is x+4, then to obtain the other factor, we divide the polynomial by the known factor.

\dfrac{9x^3 + 20x^2 - 68x - 16}{x+4} =9x^2-16x-4

Next, we factorize our result

9x^2-16x-4=9x^2-18x+2x-4\\=9x(x-2)+2(x-2)\\=(9x+2)(x-2)

Therefore, the other factors of the polynomial are 9x+2 and x-2.

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Find the difference between the polynomials:
hram777 [196]

Answer: it’s either 5x^3 -4x^2-7x or

-3x^3-4x^2-7x

Step-by-step explanation:

i put it in my calculator

3 0
3 years ago
Please help me! I’ll give Brainliest to the correct answer!!
sveta [45]

The answer will be 0


4 0
4 years ago
Solving separable differential equation DY over DX equals xy+3x-y-3/xy-2x+4y-8​
Ivanshal [37]

It looks like the differential equation is

\dfrac{dy}{dx} = \dfrac{xy + 3x - y - 3}{xy - 2x + 4y - 8}

Factorize the right side by grouping.

xy + 3x - y - 3 = x (y + 3) - (y + 3) = (x - 1) (y + 3)

xy - 2x + 4y - 8 = x (y - 2) + 4 (y - 2) = (x + 4) (y - 2)

Now we can separate variables as

\dfrac{dy}{dx} = \dfrac{(x-1)(y+3)}{(x+4)(y-2)} \implies \dfrac{y-2}{y+3} \, dy = \dfrac{x-1}{x+4} \, dx

Integrate both sides.

\displaystyle \int \frac{y-2}{y+3} \, dy = \int \frac{x-1}{x+4} \, dx

\displaystyle \int \left(1 - \frac5{y+3}\right) \, dy = \int \left(1 - \frac5{x + 4}\right) \, dx

\implies \boxed{y - 5 \ln|y + 3| = x - 5 \ln|x + 4| + C}

You could go on to solve for y explicitly as a function of x, but that involves a special function called the "product logarithm" or "Lambert W" function, which is probably beyond your scope.

8 0
2 years ago
I need the steps for 38
jasenka [17]
Ok so first, you put the sides into a ratio. The question says that triangle GKNM is congruent to triangle VRPT. From this, we know that side GK is congruent to VR. So, we write that as a ratio. Also, we know that KN is congruent to RP. We also write that as a ratio. Then, using equations, we solve for x. But, we aren't done yet; the expression for side KN is 3x-2 and, we already know that x is equal to 4.4
So, we do 3*4.4-2 which is 11.2. Therefore, side KN is equal to 11./2Then, the expression for side RP is x+4. We already know that x is equal to 4.4. So, we do 4.4+4 which is 8.4. Therefore, side RP is equal to 8.4.
Oh, and the scale factor is 4:3 or 1.33 because you do 8.4/6.3 ( you can also do 11.2/8.4)
hope this helps ;)

8 0
4 years ago
Answers? with explanations
Alinara [238K]
Okay, so basically we have:
w as width; and 6+w as length

Perimeter=2w+2l

just substitute it with the values of width and length

P=2w+2(6+w)
P=2w+12+2w
P=4w+12

So, the answer is letter B.
4 0
3 years ago
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