Answer:
d. I and III only
Step-by-step explanation:
I. The seeds should be randomly assigned to a treatment.
III. The number of successful seeds and unsuccessful seeds in each group should be at least 10.
The distribution of difference between two sample proportions :
Given :
Proportion 1 = P1 ;
Proportion 2 = P2 ;
Sample assignment for both samples 1 and 2 into the different treatment groups should be randomized, that is a simple random sampling of subjects into the treatment and control group. The sample design for difference between two sample proportions should be independent.
Finally each of the two proportions P1 and P2 should record a minimum of 10 successes and 10 non - successful Occurrences.
The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
Learn more about Error here
brainly.com/question/17062640
#SPJ4
47- 12 1/3 = 34 2/3
He needs 34 and 2/3 feet more of fabric