![\ln(4x+y)=2x-3](https://tex.z-dn.net/?f=%5Cln%284x%2By%29%3D2x-3)
Differentiate both sides wrt
:
![\dfrac{\mathrm d(\ln(4x+y))}{\mathrm dx}=\dfrac{\mathrm d(2x-3)}{\mathrm dx}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%28%5Cln%284x%2By%29%29%7D%7B%5Cmathrm%20dx%7D%3D%5Cdfrac%7B%5Cmathrm%20d%282x-3%29%7D%7B%5Cmathrm%20dx%7D)
By the chain rule, we get
![\dfrac1{4x+y}\dfrac{\mathrm d(4x+y)}{\mathrm dx}=2](https://tex.z-dn.net/?f=%5Cdfrac1%7B4x%2By%7D%5Cdfrac%7B%5Cmathrm%20d%284x%2By%29%7D%7B%5Cmathrm%20dx%7D%3D2)
![\dfrac{4+\frac{\mathrm dy}{\mathrm dx}}{4x+y}=2](https://tex.z-dn.net/?f=%5Cdfrac%7B4%2B%5Cfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%7D%7B4x%2By%7D%3D2)
Solve for
:
![4+\dfrac{\mathrm dy}{\mathrm dx}=8x+2y](https://tex.z-dn.net/?f=4%2B%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%3D8x%2B2y)
![\boxed{\dfrac{\mathrm dy}{\mathrm dx}=8x+2y-4}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%3D8x%2B2y-4%7D)
Answer:
23 chalkboards
Step-by-step explanation:
Given:
Mean length = 5 m
Standard deviation = 0.01
Number of units ordered = 1000
Now,
The z factor =
or
The z factor =
or
Z = - 2
Now, the Probability P( length < 4.98 )
Also, From z table the p-value = 0.0228
therefore,
P( length < 4.98 ) = 0.0228
Hence, out of 1000 chalkboard ordered (0.0228 × 1000) = 23 chalkboard are likely to have lengths of under 4.98 m.
Answer:
Option B, 22
Step-by-step explanation:
Alternate interior angles are same
Answer:
1 x=-2.5 y = -5.5
2. x=5 y=1
Step-by-step explanation:
1) What is the solution of the given system?
5x-y=-7
3x-y=-2
Multiply the second equation by -1
-1*(3x-y)=-1(-2)
-3x +y = 2
Now add the first equation to the modified second equation
5x-y=-7
-3x +y = 2
------------------
2x = -5
Divide each side by 2
2x/2 = -5/2
x = -2.5
Now we need to find y
-3x+y =2
-3(-2.5) +y =2
7.5 +y =2
Subtract 7.5 from each side
7.5 -7.5 +y =2-7.5
y = -5.5
2) what is the solution of the given system?
5x+7y=32
8x+6y=46
Divide the second equation by 2
8x/2+6y/2=46/2
4x+3y =23
Multiply the first equation by 4
4 (5x+7y)=32*4
20x+28y = 128
Now multiply the modified 2nd equation by -5
-5(4x+3y )=-5(23
)
-20x -15y = -115
Lets add the new equations together to eliminate x
20x+28y = 128
-20x -15y = -115
---------------------
13y = 13
Divide each side by 13
13y/13 =13/13
y=1
Now substitute back in to find x
5x+7y=32
5x +7(1) =32
5x +7 =32
Subtract 7 from each side
5x+7-7 =32-7
5x =25
Divide by 5
5x/5 =25/5
x=5
Question:
Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26.
What is the solution set of this problem?
Answer:
![x \leq -21](https://tex.z-dn.net/?f=x%20%5Cleq%20-21)
Step-by-step explanation:
Given
<em>Represent the number with x</em>
So:
![5 * (x + 27) \geq 6 * (x + 26)](https://tex.z-dn.net/?f=5%20%2A%20%28x%20%2B%2027%29%20%5Cgeq%206%20%2A%20%28x%20%2B%2026%29)
Required
Determine the solution set
![5 * (x + 27) \geq 6 * (x + 26)](https://tex.z-dn.net/?f=5%20%2A%20%28x%20%2B%2027%29%20%5Cgeq%206%20%2A%20%28x%20%2B%2026%29)
Open Both Brackets
![5 * x + 5 * 27 \geq 6 *x + 6 * 26](https://tex.z-dn.net/?f=5%20%2A%20x%20%2B%205%20%2A%2027%20%5Cgeq%206%20%2Ax%20%2B%206%20%2A%2026)
![5x + 135 \geq 6x + 156](https://tex.z-dn.net/?f=5x%20%2B%20135%20%5Cgeq%206x%20%2B%20156)
Collect Like Terms
![5x - 6x \geq 156-135](https://tex.z-dn.net/?f=5x%20-%206x%20%5Cgeq%20156-135)
![- x \geq 21](https://tex.z-dn.net/?f=-%20x%20%5Cgeq%2021)
Multiply both sides by -1
![x \leq -21](https://tex.z-dn.net/?f=x%20%5Cleq%20-21)
Hence, the solution set is ![x \leq -21](https://tex.z-dn.net/?f=x%20%5Cleq%20-21)