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liq [111]
3 years ago
7

(3x-4) (6x+7) Multiply those binomials.

Mathematics
2 answers:
mario62 [17]3 years ago
6 0
18x^3-3x-28. hope this helps :)
tensa zangetsu [6.8K]3 years ago
6 0

Answer:

18x^2 +21x -24x -28 = 18x^2 -3x -28

Step-by-step explanation:

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Which of the following constructions is this?
ohaa [14]

Answer:

acute hope it helps

Step-by-step explanation:

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8 0
3 years ago
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Aeva is selling friendship pins as a service project. Each pin with green beads sells for $3. Each pin with red beads sells for
Luba_88 [7]

Answer:69

Step-by-step explanation:

69•2= 138

69-11=58

58•3=174

174+138=312

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This is a linear equation/ graph quiz ! please help , my teacher makes no sense to me!
JulijaS [17]

Answer:

(8,5)

Step-by-step explanation:

5x - 2y = 30

coordinates are (x,y) so you plug in 8 for x and solve for y

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subtract 40 from both sides to isolate y

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6 0
3 years ago
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If a =-2 and b= 2 what will be the value of a^b
raketka [301]
Write out the equation;

y=a^b 
y=(-2)^2 
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Therefore, the value of a^b is 4 

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7 0
3 years ago
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Each letter of the word "supercalifragilisticexpialidocious" is placed into a bag and drawn at 3 times, replacing the letter aft
Makovka662 [10]

Answer:

P(X ≥ 1) = 0.50

Step-by-step explanation:

Given that:

The word "supercalifragilisticexpialidocious" has 34 letters in which 'i' appears 7 times in the word.

Then; the probability of success = 7/34 = 0.20588

Using Binomial distribution to determine the probability; we have:

P(X = x)  = ^nC_x  \ \beta^x   \  (1 - \beta)^{n-x}

where;

x = 0,1,2,...n    and    0  <  β   <   1

and x represents the  number of successes.

However; since the letter is drawn thrice; the probability that the letter "i" is drawn at least once can be computed as:

P(X ≥ 1) = 1 - P(X< 1)

P(X ≥ 1) = 1 - P(X =0)

P(X \ge 1) =  1 - \bigg [ {^3C__0} (0.21)^0 (1-0.21)^{3-0} \bigg]

P(X \ge 1) =  1 - \bigg [ 1 \times 1 (0.79)^{3} \bigg]

P(X ≥ 1) = 1 - 0.50

P(X ≥ 1) = 0.50

4 0
3 years ago
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