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liq [111]
3 years ago
7

(3x-4) (6x+7) Multiply those binomials.

Mathematics
2 answers:
mario62 [17]3 years ago
6 0
18x^3-3x-28. hope this helps :)
tensa zangetsu [6.8K]3 years ago
6 0

Answer:

18x^2 +21x -24x -28 = 18x^2 -3x -28

Step-by-step explanation:

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What is the value of angle v?
Flauer [41]

Answer:

x = 5

Step-by-step explanation:

a) The third interior angle of this triangle is 180 - 20 x.  

The three interior angles must sum up to 180 degrees.

Therefore,  60 + 7x + 5 + 180 - 20x = 180, or

                       65  + 180 - 13x = 180, or

                               65 -  13x     = 0

Finally, 13x = 65, and so x = 5

7 0
3 years ago
2hat is the sum of 2x-5y need help asap plz
damaskus [11]
Because these are not like terms, they cannot be combined. The variables are different, that's what makes them not like terms
4 0
3 years ago
1. The full Renegade dance Jalaiah created is 56 seconds long. For a 15-second-long TikTok, what percent of Renegade is used?​
VikaD [51]

Answer:

3.7

Step-by-step explanation:

You have to divide

6 0
3 years ago
Read 2 more answers
Simplify the expression. 12x^-6 y^10 times 3x^7 y
Vlada [557]

We need to simplify the expression:

12x^{-6}y^{10} \times (3x^{7}y)

Now, we know that we can resolve the exponents of the variables with the like terms only and we can multiply the coefficients independently:

Now,  

12x^{-6}y^{10} \times 3x^{7}y=(12 \times 3)\times (x^{-6}\times x^{7})\times (y^{10}\times y)

On simplifying the above expression we get:

36\times x^{(-6+7)}\times y^{(10+1)}

=36 \times x^{1}\times y^{11}

=36 \times x \times y^{11}

=36xy^{11}

So the simplified form of the expression 12x^{-6}y^{10} \times 3x^{7}y=36xy^{11}.

7 0
3 years ago
3x to the power of 3 + 21x squared + 36x = 0 by factoring the quadratic equation.
Diano4ka-milaya [45]

Answer:

x = 0, -4 and -3.

Step-by-step explanation:

The given expression is "3x to the power of 3 + 21x squared + 36x = 0".

We can write this expression as follows :

3x^3+21x^2+36x=0

Taking 3x common.

3x(x^2+7x+12)=0\\\\3x=0\ \text{and}\ (x^2+7x+12)=0

x = 3

x^2+7x+12=0\\\\x^2+3x+4x+12=0\\\\x(x+3)+4(x+3)=0\\\\(x+4)(x+3)=0\\\\x=-4,-3

Hence, the solution of the given quadratic equation are x = 0, -4 and -3.

5 0
3 years ago
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