All categories

3 years ago

A grocery store sells steak for $6.10 per pound. What would be the cost of 2 3/5 lb of steak?

Mathematics

2 answers:

Gnesinka [82]3 years ago

8 0

Answer: The answer is $15.86

Step-by-step explanation: You would change 6.10 into a fraction, which is 61/10. Then you would mulitply that and that number as a decimal would be 15.86.

trasher [3.6K]3 years ago

8 0

Answer:

$15.86

Step-by-step explanation:

You divide 6.10 by 5 and you get 1.22 then u multiply 1.22 by 3 and you get 3.66 and add 6.10 and 6.10 and 3.66 to get your answer.

You might be interested in

5,114 what is the 1s value?

Leokris [45]

The ones place value is four

4 0

3 years ago

Read 2 more answers

HELP ME THANKS +×+

Tresset [83]

Answer:

$hypotenuse = \sqrt{ {height}^{2} + {adjacent}^{2} } \\ = \sqrt{ {11}^{2} + {60}^{2} } \\ = \sqrt{3721} \\ = 61 \: inches$

4 0

3 years ago

Read 2 more answers

Below are survival times (in days) of 13 guinea pigs that were injected with a bacterial infection in a medical study:

tresset_1 [31]

Outliers are data that are relatively far from other data elements.

The dataset has an outlier and the outlier is 120

The dataset is given as:

91 83 84 79 91 93 95 97 97 120 101 105 98

Sort the dataset in ascending order

79 83 84 91 91 93 95 97 97 98 101 105 120

<h3>The lower quartile (Q1)</h3>

The Q1 is then calculated as:

$Q1 = \frac{N +1}{4}th$

So, we have:

$Q1 = \frac{13 +1}{4}th$

$Q1 = \frac{14}{4}th$

$Q1 = 3.5th$

This is the average of the 3rd and the 4th element

$Q1 = \frac{1}{2} \times (84 + 91)$

$Q1 = 87.5$

<h3>The upper quartile (Q3)</h3>

The Q3 is then calculated as:

$Q3 = 3 \times \frac{N +1}{4}th$

So, we have:

$Q3 = 3 \times \frac{13 +1}{4}th$

$Q3 = 3 \times 3.5th$

$Q3 = 10.5th$

This is the average of the 10th and the 11th element.

$Q_3 =\frac12 \times (98 + 101)$

$Q_3 =99.5$

<h3>The interquartile range (IQR)</h3>

The IQR is then calculated as:

$IQR = Q_3 -Q_1$

$IQR = 99.5 - 87.5$

$IQR = 12$

Also, we have:

$IQR(1.5) = 12 \times 1.5$

$IQR(1.5) = 18$

<h3>The outlier range</h3>

The lower and the upper outlier range are calculated as follows:

$Lower = Q_1 - IQR(1.5)$

$Lower = 87.5- 18$

$Lower = 69.5$

$Upper = Q_3 + IQR(1.5)$

$Upper = 99.5 + 18$

$Upper = 117.5$

120 is greater than 117.5.

Hence, the dataset has an outlier and the outlier is 120

Read more about outliers at:

brainly.com/question/9933184

6 0

2 years ago

Select the correct answer.<br> Which of the following sets of ordered pairs represents a function?

iogann1982 [59]

Answer: {(-8, -14), (-7,-12), (-6,-10), (-5,-8)}

Step-by-step explanation: A function is a relation in which each x-coordinate corresponds to exactly one y-coordinate.

In the relations show here, notice that the first set

of ordered pairs is the only set where each x-coordinate

appears once with a different y-coordinate.

In the other ordered pairs, there is an x-coordinate that appears more

than once and it corresponds to a different y-coordinate.

For example, in the second relation,

the x-coordinate -9 appears twice.

In one case, -9 corresponds to -12 and

in the other case, it corresponds to -8.

So, this is not a function.

3 0

3 years ago

Use the drop-down menus to complete each equation so the statement about its solution is true.

disa [49]

Answer:

Step-by-step explanation:

So,it would be easier to simplify the right equation, so when I say "the right equation", I mean the one I will make right now. It is 8x+9. So the first problem is 8x+9=x+?. Well, if there are no solutions, the slopes have to be the same, and the y-int doesn't matter. So the answer would be + 7x because that will make the x an 8x. If there is one solution, then the slope has to be different. So literally anything but 7x will work. Even constants. If there are infinitely many solutions, then the equations have to be the same. Meaning, you would have to add 7x and 9 to make the left equation the same as the right.

6 0

2 years ago