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USPshnik [31]
3 years ago
7

Deanna is investigating transformations that carry a regular polygon onto itself. She claims that for a regular polygon of k sid

es, the minimum angle of rotation about its center that carries it onto itself is equal to the measure of each interior angle of the polygon. For what value of k would Deanna's claim be true?
Mathematics
1 answer:
bazaltina [42]3 years ago
7 0

Answer:

The value of k that would make Deanna's claim to be true is k = 4

Step-by-step explanation:

The given transformation that Deanna has a claim for = Rotation

Deanna's claim. the minimum rotation of a polygon about its center that carries the polygon onto itself = The interior angle of the polygon

We note that the rotation of a regular polygon about its center that carries the polygon onto itself = The exterior angle of the polygon

Therefore, given that for a polygon with more than 5 sides, the exterior angle of the polygon < The interior angle of the polygon, Deana statement can be said to be true for the case of a square

Here;

The exterior angle of the polygon = The interior angle of the polygon 90

The value of k which is the number of sides of the polygon, for a square = 4

Therefore, the value of k that would make Deanna's claim to be true is k = 4.

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Write all the factors of 9 . Use commas to separate them.rtth
Rasek [7]

Answer:

1, 3, 9

Step-by-step explanation:

the nine can be divided by those three numbers and no more

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3 years ago
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What is the result when the following code is run? double x = 1; double y = 1; int i = 0; do { y = x / 2; x = x + y; i = i + 1;
Mama L [17]

Answer:

The answer is: 3

Step-by-step explanation:

1. At the begining of the program we start by declairing the variables:

 double x=1, double y=1 and int i=0.

2. The structure do...while is used to defined the loop. x<2.5 is the finalization condition of the loop. i is the counter of the loop.

y=x/2 is the first calculation

x=x+y is the second one. Here is where the values of the variable x changes.

a) for the first iteration, the values of y and x are shown below:

\\\\x=1\\y=1\\y=1/2=0.5\\x=1+0.5=1.5\\i=1

The variable x is minor to 2.5 so the loop will continue computing.

b)   the second iteration, the values of y and x are shown below::

 y=0.5\\x=1.5\\y=\frac{1.5}{2}=0.75\\ x=1.5+0.75=2.25\\i=2

The variable x is still minor to 2.5 so the loop will continue computing.

c) third iteration:

y=0.75\\x=2.25\\y=\frac{2.25}{2} =1.1125\\x=2.25+1.125=3.375\\i=3

The condition x<2.5 is not true so the loop ends.

3. System.out.print(i + " "); displays the value of the variable i wich value is 3.

Therefore the number 3 is display.

6 0
3 years ago
Will give brainliest need quick answers
natali 33 [55]

Answer:

u=1

v = 10

Step-by-step explanation:

For the triangles to be congruent

IG = PR

50 = u+49

50 - 49 = u

1 = u

GH = RQ

v+6 = 16

v = 16-6

v = 10

7 0
3 years ago
You have a list of 1,000 random, normally distributed numbers with a mean of 20 and a standard deviation of 3. Which statement i
Ludmilka [50]
You're going to have to work out the z-scores of both values in each option and see if it makes sense.

n = m + sz

The mean is 20 and the standard deviation is 3.

So let's find try the z-scores of the outer range values and determine their probabilities:

from 14-20:

n = m + sz
20 = 20 + 3z and 14 = 20 + 3z
0 = 3z and -6 = 3z
z = 0 and z = -2

So now using a z-score table, such as the one below, find the probabilities.

z = 0 is easy, it's 0.5
z = -2 is 0.02275

Subtract the smaller from the larger to get the probability of getting in the range:

0.5 - 0.02275 = 0.47725 (so times 1000, you get 477.25, which is not about 340, so this option is wrong)
---
Now trying option 2, from 17-29:

n = m + sz
29 = 20 + 3z and 17 = 20 + 3z
9 = 3z and -3 = 3z
z = 3 and z = -1

0.99865 - 0.158655 = 0.839995 (not 680, so not the answer)
---
Now trying option 3, from 20-23:

n = m + sz
23 = 20 + 3z and 20 = 20 + 3z
3 = 3z and 0 = 3z
z = 1 and z = 0

0.841345 - 0.5 = 0.341345 (close to 340, so is your answer)
8 0
3 years ago
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