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3 years ago

The points (0, −6) and (−10, 4) lie on the graph of a linear function.

Mathematics

2 answers:

Paraphin [41]3 years ago

8 0

What was the correct answer for this question ??

Everyone keeps saying its (-10,-10) is this answer correct ??

Montano1993 [528]3 years ago

3 0

-10, -10 is the answer

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What is m∠V?

Bezzdna [24]

We know that
Applying the law of cosines

c²=a²+b²-2*a*b*cos C------> cos C=[a²+b²-c²]/[2*a*b]

in this problem

a=7.6 in

b=8.6 in

c=7.4 in

C=angle V

cos C=[7.6²+8.6²-7.4²]/[2*7.6*8.6]----> 0.5887

C=arc cos (0.5887)--------> C=53.93°-------> C=53.9°

the answer is

angle V is 53.9°

5 0

3 years ago

Why does the sum of -4 and 3 complain more than the sum of -3 and 5

AlexFokin [52]

Because of its negatives

7 0

3 years ago

The average temperature in the North Pole in the summer is 32 degrees F. The average temperature in the North Pole in the winter

wlad13 [49]

Answer:

he counted from 32 to 40 , and not to -40

Step-by-step explanation:

the difference is 72 degrees

7 0

3 years ago

Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2, and the profit

Mademuasel [1]

<u>Answer:</u>

$y = -\frac{2}{3}x + 490$

gradient = = $-\frac{2}{3}$

y-intercept = $490$

<u>Step-by-step explanation:</u>

• The slope-intercept form of an equation takes the general form:

$\boxed{y = mx + c}$ ,

where:

m = slope,

c = y-intercept.

• We are given the equation:

$2x + 3y = 1470$

To change this into the slope-intercept form, we must make y the subject:

$3y = -2x + 1470$ [subtract $2x$ from both sides]

⇒ $y = -\frac{2}{3}x + \frac{1479}{3}$ [divide both sides by 3]

⇒ $y = -\frac{2}{3}x + 490$

• Comparing this equation with the general form equation, we see that:

m = $-\frac{2}{3}$

c = $490$ .

This means that the gradient is $\bf -\frac{2}{3}$ , and the y-intercept is $\bf 490$ .

6 0

2 years ago

A track star runs two races on a certain day. The probability thathe wins the first race is 0.7, the probability that he wins th

NARA [144]

Answer:

a) 80% probability that he wins at least one race.

b) 30% probability that he wins exactly one race.

c) 20% probability that he wins neither race.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that he wins the first race.

B is the probability that he wins the second race.

C is the probability that he does not win any of these races.

We have that:

$A = a + (A \cap B)$

In which a is the probability that he wins the first race but not the second and $A \cap B$ is the probability that he wins both these races.

By the same logic, we have that:

$B = b + (A \cap B)$

The probability that he wins both races is 0.5.

This means that $A \cap B = 0.5$

The probability that he wins the second race is 0.6

This means that $B = 0.6$

$B = b + (A \cap B)$

$0.6 = b + 0.5$

$b = 0.1$

The probability that he wins the first race is 0.7.

This means that $A = 0.6$

$A = a + (A \cap B)$

$0.7 = a + 0.5$

$a = 0.2$

A) he wins at least one race.

This is

$P = a + b + (A \cap B) = 0.2 + 0.1 + 0.5 = 0.8$

There is an 80% probability that he wins at least one race.

B) he wins exactly one race.

This is

$P = a + b = 0.2 + 0.1 = 0.3$

There is a 30% probability that he wins exactly one race.

C) he wins neither race

Either he wins at least one race, or he wins neither. The sum of these probabilities is 100%.

From a), we have that there is an 80% probability that he wins at least one race.

So there is a 100-80 = 20% probability that he wins neither race.

6 0

3 years ago