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Studentka2010 [4]
3 years ago
15

Help with question 3

Mathematics
1 answer:
slega [8]3 years ago
4 0
6.4166666666666666666667
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Find the sum of the geometric series given a1=2, r=−3, and n=8.
inn [45]

Answer:

<u>Sum</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>G</u><u>.</u><u>P</u><u> </u><u>is</u><u> </u><u>-</u><u>3</u><u>2</u><u>8</u><u>0</u>

Step-by-step explanation:

Summation:

{ \bf{sum =  \frac{a( {r}^{n }-1 )}{r - 1} }} \\  \\ { \tt{sum =  \frac{2( { { - 3}^{8 } -1)} }{ - 3 - 1} }} \\ { \tt{ =  \frac{13120}{-4} }} \\  = -3280

3 0
3 years ago
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Find the common ratio of the following geometric sequence.
Elanso [62]
The answer is (4/5). If you multiply the first (5/12) over and over, you get this sequence.
8 0
3 years ago
F(x)=x^(2)+3x+4 is this quadratic, linear, or neither
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8 0
2 years ago
PLZ HELP INSCRIBED ANGLES
den301095 [7]
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7 0
3 years ago
Joe sold a total of 10 baked goods. Each cookie costs $1.25 and each brownie costs $2.50. Joe made $20 at the bake sale. How man
AURORKA [14]

Answer:

4 cookies

Step-by-step explanation:

Let the number of cookies he sold be c and that of brownies be b.

Assuming that brownies and cookies are the only type of baked goods sold,

b +c= 10 -----(1)

Amount of money received= $20

b(cost of brownie) +c(cost of cookie)= $20

2.50b +1.25c= 20 -----(2)

From (1): b= 10 -c -----(3)

Substitute (3) into (2):

2.50(10 -c) +1.25c= 20

Expand:

2.50(10) +2.50(-c) +1.25c= 20

25 -2.50c +1.25c= 20

-1.25c +25= 20

Being constants to 1 side:

-1.25c= 20 -25

-1.25c= -5

c= -5 ÷(-1.25)

c= 4

Thus, Joe sold 4 cookies.

8 0
2 years ago
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