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Katena32 [7]
3 years ago
9

A rectangular blanket’s perimeter is 210 inches. If the long sides of the blanket measure 60 inches, what is the length of the s

horter sides of the blanket?
Mathematics
1 answer:
Annette [7]3 years ago
7 0
45 because you do 210-120 which is 90. 90÷2 is 45. -JZ
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If the length of a cuboid is 60cm and width 40cm and its surface area is 14800cm² find its height
kherson [118]
Formula of surface area of cuboid = 2(lb+bh+lh) . Surface area of cuboid is 14800cm^2 (Given) then 14800 = 2(60*40+40*Height+Height*60) 14800= 2(2400+40*H+H*60) 14800= 4800+80*2H+2H*60 14800= 4880*4H*60 14800/4880*60= 4H
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3 0
2 years ago
Read 2 more answers
If n erasers have a weight of 80 grams, what is the total weight of 50 erasers?
Black_prince [1.1K]

Answer:

The\ weight\ of\ the\ 50\ erasers\ be\ \frac{4000}{n}\ grams.

Step-by-step explanation:

As given

if n erasers have a weight of 80 grams .

I.e

n erasera =  80 grams.

1 erasers weight .

1\ erasers\ weight = \frac{80}{n}

Now find out the weight of the 50 erasers.

Weight\ of\ 50\ erasers = \frac{50\times 80}{n}\ grams

Simplify the above

Weight\ of\ 50\ erasers = \frac{4000}{n}\ grams

Therefore\ the\ weight\ of\ the\ 50\ erasers\ be\ \frac{4000}{n}\ grams.

6 0
3 years ago
Read 2 more answers
Prove <5 is supplementary to <6 using theorems.
babunello [35]

Answer:

Theorem 10.5: If two parallel lines are cut by a transversal, then the exterior angles on the same side of the transversal are supplementary angles.

6 0
2 years ago
Given the points (-4,8)and(6,-12)
MissTica

Answer:

1.

midpoint = ( \frac{ - 4 + 6}{2} , \:  \frac{ - 12 + 8}{2} ) \\  = (1, \:  - 2)

2.

distance =  \sqrt{ {( - 4 - 6)}^{2} +  {( - 12 - 8)}^{2}  }  \\  =  \sqrt{500}  \\  = 22.4 \: units

3 0
2 years ago
Con las cuatro cartas que se muestran en la figura se pueden formar diferentes números. Por ejemplo: 8232 o 3822. ¿Cuántos númer
densk [106]

Answer:

Se pueden formar 9 números pares.

Step-by-step explanation:

Dado que con cuatro cartas se pueden formar diferentes números, como por ejemplo 8232 o 3822, para determinar cuántos números pares de cuatro dígitos y diferentes puedes formar con estas cuatro cartas se debe realizar la siguiente tabla:

8232 - 8322 - 8223 = 2 pares 1 impar

2832 - 2823 - 2382 - 2328 - 2283 - 2238 = 4 pares 2 impares

3822 - 3282 - 3228 = 3 pares

Por lo tanto, se pueden formar 9 números pares.

5 0
3 years ago
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