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3 years ago

9

A rectangular blanket’s perimeter is 210 inches. If the long sides of the blanket measure 60 inches, what is the length of the s

horter sides of the blanket?

1 answer:

Annette [7]3 years ago

7 0

45 because you do 210-120 which is 90. 90÷2 is 45. -JZ

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From three chocolate bars we can make at most five chocolate rabbits and

Luden [163]

Answer: About 49.

Explanation:

16 × 3 = 48.

With some left over, you can infer they can make atleast 1 more bar.

48 + 1 = About 49 chocolate bars.

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3 years ago

What is the greatest fraction you can make using the digits 4, 7, and 9?

wel

Answer:

(7^9)/4 = 40,353,607/4

Step-by-step explanation:

Assuming each digit is used once and exponentiation is allowed, the largest numerator and smallest denominator will result in the largest fraction.

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If other functions, such as factorial are allowed, then there might need to be a limit on the number of times they are applied. For example,

(7!)^(9!)/4 has about 1 million digits

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((7!)^(9!))!/4 has many more digits than that

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3 years ago

If you can answer any of these that would be great !

Andrej [43]

Answer:

Step-by-step explanation:

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2 years ago

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Determine the domain of the function (fog)(x) where f(x)=3x-1/x-4 and g(x)=x+1/x

Katarina [22]

Answer: (-∞,-1) ∪ (0,+∞)

Step-by-step explanation: The representation fog(x) is a representation of composite function, meaning one depends on the other.

In this case, fog(x) means:

fog(x) = f(g(x))

fog(x) = $3(x+\frac{1}{x} )-\frac{1}{x+\frac{1}{x} } -4$

$fog(x)=3x+\frac{3}{x} -\frac{1}{\frac{x^{2}+x}{x} } -4$

$fog(x)=3x+\frac{3}{x} -\frac{x}{x^{2}+x} -4$

$fog(x)=\frac{3x^{2}(x^{2}+x)+3(x^{2}+x)-x-4x(x^{2}+x)}{x(x^{2}+x)}$

$fog(x)=\frac{3x^{4}+3x^{3}+3x^{2}+3x-x-4x^{3}+4x^{2}}{x(x^{2}+x)}$

$fog(x)=\frac{3x^{4}-x^{3}-x^{2}+2x}{x(x^{2}+x)}$

This is the function fog(x).

The domain of a function is all the values the independent variable can assume.

For fog(x), denominator can be zero, so:

$x(x^{2}+x) \neq 0$

If x = 0, the function doesn't exist.

$x^{2}+x \neq0$

$x(x+1) \neq0$

$x+1\neq0$

$x\neq-1$

<u>Therefore, the domain of this function is: </u><u>-∞ < -1 or x > 0</u>

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3 years ago