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nexus9112 [7]
3 years ago
14

Find the absolute maximum and absolute minimum values of f on the given interval. f(x) = 4x3 − 6x2 − 24x + 1, [−2, 3] absolute m

inimum value absolute maximum value

Mathematics
1 answer:
Agata [3.3K]3 years ago
7 0

When looking for extremes on an interval, one must examine the turning points and the values of the function at the ends of the interval. Here the turning points are where the derivative is zero:. j

... 12x² -12x -24 = 0

... 12(x -2)(x +1) = 0

Since the turning points, x=-1, x=2, are in the interval we have four function values to compute.

... f(-2) = ((4(-2) -6)(-2) -24)(-2) +1 = -7

... f(-1) = ((4(-1) -6)(-1) -24)(-1) +1 = 15

... f(2) = ((4(2) -6)(2) -24)(2) +1 = -39

... f(3) = ((4(3) -6)(3) -24)(3) +1 = -17

This shows the extremes to be at the turning points.

The absolute minimum value is -39 at x=2.

The absolute maximum value is 15 at x=-1.

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The inequality that represents the domain of the function is \frac 12x - 10 \ge 0

<h3>How to determine the domain?</h3>

The function is given as:

f(x) = \sqrt{\frac 12x - 10} + 3

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Multiply through by 2

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Read more about domain at:

brainly.com/question/1770447

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Step-by-step explanation:

I think that's what it's asking??

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Answer:

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Step-by-step explanation:

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