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OleMash [197]
3 years ago
14

If a coin is tossed twice find the probability of getting a) 2 heads b) atleast 1 head c) no heads

Mathematics
2 answers:
Vilka [71]3 years ago
4 0

Answer:

a) 1/4

b) 3/4

c) 1/4

Step-by-step explanation:

Possible outcomes of two tosses of a coin:

HH

HT

TH

TT

There is a total of 4 possible outcomes.

p(event) = (number of desired outcomes)/(total number of possible outcomes)

a) 2 heads

HH     <-------  1 desired outcome

HT

TH

TT

p(2 heads) = 1/4

b) at least 1 head

HH   \  

HT      }     <------ 3 desired outcomes

TH    /

TT

p(at least 1 head) = 3/4

c) no heads

HH

HT

TH

TT    <------- 1 desired outcome

p(no heads) = 1/4

spayn [35]3 years ago
3 0

Answer:

B

Step-by-step explanation:

A coin has two sides so there is a 50% chance of getting heads or tails.

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I wasn't in school today can someone explain how to do this
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Give the properties for the equation -2x 2 - y + 10x - 7 = 0.
Sladkaya [172]

Given:

The quadratic equation is

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To find:

The vertex of the given quadratic equation.

Solution:

If a quadratic function is f(x)=ax^2+bx+c, then

Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)

We have,

-2x^2-y+10x-7=0

It can be written as

-2x^2+10x-7=y

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Here, a=-2,b=10,c=-7.

\dfrac{-b}{2a}=\dfrac{-10}{2(-2)}

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y=-2(\dfrac{5}{2})^2+10(\dfrac{5}{2})-7

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y=\dfrac{-50}{4}+25-7

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Therefore, the correct option is A.

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