Question

Nine years ago, a woman was three times as old as her son. In eight years from now, the sum of

Answer 1

Answer:

she would would be about 61 years and her son about 20 years

Step-by-step explanation:

78-9=69

70-8=61

61/3=20.3

Answer 2

Answer:

Step-by-step explanation:

Today woman is x, son is y

x-9=3(y-9)

x-9=3y-27

3y-x=18

in 8 years x+8 and y+8 and that sum is 78, so x+y+16=78

x+y=62

x=62-y

so 3y-62+y=18

4y=80

y=20 son

x=42 mother

nine years earlier it was 33 and 11

8 years from now it will be 50 and 28

8 years from now is suppose to = 78 and 50+28=78

Since 8 years from now they the woman is 42 and the son is 20.

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