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xxMikexx [17]
3 years ago
11

Are these shapes similar or congruent?

Mathematics
1 answer:
aliya0001 [1]3 years ago
4 0

Answer:

Congruent

Step-by-step explanation:

Hope this helps you!!

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viktelen [127]
B is equal to the number 24.

7 0
3 years ago
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BIG IDEAS MATH
IgorC [24]

Answer:

106

Step-by-step explanation:

See attached

7 0
2 years ago
Write the equation for Chelsea's graph in
xeze [42]

Answer:

y=-4x+16.

Step-by-step explanation:

From the given graph it is clear that the y-intercept is 16.

The line passes through (-2,24) and (2,8). So, slope of line is

Slope=\dfrac{y_2-y_1}{x_2-x_1}

Slope=\dfrac{8-24}{2-(-2)}

Slope=\dfrac{-16}{4}

Slope=-4

Slope intercept form of a line is

y=mx+b

where, m is slope and b is y-intercept.

Substitute m=-4 and b=16 in the above equation.

y=(-4)x+(16)

y=-4x+16

Therefore, the required equation is y=-4x+16.

6 0
3 years ago
In an election, everyone voted for either Cindy or Shawn. Cindy received 55% of the votes. Shawn received 423 votes. How many to
kirill [66]
100-55=45%

45/100 × x = 423
x = (423)/(45/100)
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3 0
3 years ago
A 2-column table with 7 rows. The first column is labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2, 3. The sec
DochEvi [55]

The statements that are true about the intervals of the continuous function are Options 2, 4  and 5

  • f(x) ≤ 0 over the interval [0, 2].
  • f(x) > 0 over the interval (–2, 0).
  • f(x) ≥ 0 over the interval [2, ).

<h3>What is the statement about?</h3>

Looking at the values given, the intervals which satisfies the condition are known to be:

f(x)<=0 over the interval [0,2]

f(x)>0 over the interval (-2,0)

f(x)>=0 over the interval [2,∞)

Because:

Since the table with x  and f(x) values, we have to examine analyze the table and see the each option that is in line with f(x) or not .

Examine the values of x that is from -3 to 3, the f(x) values are both positive and negative . hence f(x)>0 is false over the interval (-∞,3)

Looking at the the interval from 0 to 2, the f(x) values are 0 and negative. Hence, f(x)<=0 over the interval [0,2]

When you look over the interval (-1,1), the f(x) values are said to be both positive and negative and as such, f(x)<0 is false over the interval (-1,1)

When you look at the interval (-2,0) , the f(x)  is positive and as such, f(x)>0 over the interval (-2,0)

Looking at the interval  [2,∞), f(x) is positive and as such, f(x)>=0 over the interval [2,∞)

Therefore, Option 2, 4 and 5 are correct.

Learn more about interval from

brainly.com/question/14454639

#SPJ1

6 0
2 years ago
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