Given:
The graph of a quadratic function passes through the points (5,31) (3,11) (0,11).
To find:
The equation of the quadratic function.
Solution:
A quadratic function is defined as:
...(i)
It is passes through the point (0,11). So, substitute
in (i).


Putting
in (i), we get
...(ii)
The quadratic function passes through the point (5,31). So, substitute
in (ii).

Divide both sides by 5.
...(iii)
The quadratic function passes through the point (3,11). So, substitute
in (ii).
Divide both sides by 3.
...(iv)
Subtracting (iv) from (iii), we get




Putting
in (iv), we get



Putting
in (ii), we get
Therefore, the required quadratic equation is
.
Answer:
9
Step-by-step explanation:
Firstly you can simplify the exponents shown below:

Simply add exponents when multiplying like shown above.
Answer:
length: 5 yd
width: 4 yd
area: 20 yd^2
Step-by-step explanation:
1 yd = 3 ft
15 ft * (1 yd)/(3 ft) = 5 yd
12 ft * (1 yd)/(3 ft) = 4 yd
A = LW
A = 5 yd * 4 yd = 20 yd^2
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M is the slope of the equation.
Hope this helps!