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Rus_ich [418]
3 years ago
14

A number that multiplies a variable in a term is a ___

Mathematics
1 answer:
adelina 88 [10]3 years ago
4 0
It’s gonna be B coefficient
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I need help with this
Alex73 [517]

Answer: the third one

Step-by-step explanation:

3 0
3 years ago
Y=-2x²-8x-5 domain and range
Jobisdone [24]

Answer:

Domain: All real numbers

Range: y≤3

Step-by-step explanation:

The given function is

y =  - 2 {x}^{2}  - 8x - 5

This is a polynomial function.

The domain is set of all values of x, that makes this function defined.

Since polynomial functions are defined everywhere, the domain is all real numbers.

To find the range we put the function in vertex form:

y =  - 2( {x}^{2}  + 4x) - 5

y =  - 2( {x}^{2}  + 4x + 4) - 5 +  - 4 \times  - 2

y =  - 2( {x}  + 2)^{2} - 5 + 8

y =  - 2( {x}  + 2)^{2}  +  3

The maximum value is 3

The function turns downward, hence the range is:

y \leqslant 3

6 0
3 years ago
Which expressions do you get when you eliminate the negative exponents of .........
kvasek [131]

Answer:

D. 4(a^2)(a^3)/16(b)(b^2)

Step-by-step explanation:

5 0
3 years ago
Jim makes the chart shown below to prove that Triangle APD is congruent to triangle BPC:
Oliga [24]

Answer:

Given a square ABCD and an equilateral triangle DPC and given a chart with which Jim is using to prove that triangle APD is congruent to triangle BPC.

From the chart, it can be seen that Jim proved that two corresponding sides of both triangles are congruent and that the angle between those two sides for both triangles are also congruent.


Therefore, the justification to complete Jim's proof is "SAS postulate"



Step-by-step explanation:


6 0
3 years ago
Solve<br> h-w<br> Solve m = for the<br> 8<br> variable h.<br> I
Ilya [14]

Answer:

1) m = h - w/8

Subtract h from both sides.

m - h = -w/8

Subtract m from both sides.

-h = -m - w/8

Divide all terms by -1.

h = m + w/8.

2) m = h - w/8

Get rid of the denominator 8 by multiplying 8/1 to all terms.

8m = 8h - w

Add w on both sides and subtract 8m from both sides.

w = 8h - 8m

3) w = x + y/z

Get rid of the denominator z by multiplying it to all terms.

wz = xz + y

Subtract xz from both sides of the equation.

wz - xz = y OR y = wz - xz

4) w = x + y/z

Subtract x from both sides.

w - x = y/z

Get rid of the denominator by multiplying it to all terms.

wz - xz = y

Now factor the expression wz - xz.

z(w - x) = y

Divide both sides by w - x.

z = y / w - x

This is read as z equals to y divided by w minus x.

5) The area of a triangle is A = 1/2bh

First, get rid of the denominator by multiplying both sides by 2.

2A = bh

To find b, divide both sides by h.

2A/h = b

6) P = kt/v

Multiply both sides by v.

Pv = kt

Divide both sides by t.

Pv/t = k OR k = Pv/t.

Step-by-step explanation:

8 0
3 years ago
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