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Firdavs [7]
3 years ago
7

What is 121,580 rounded to the nearest thousand

Mathematics
1 answer:
faust18 [17]3 years ago
7 0

122,000

The number in the hundredth place is a 5 so that makes the number in the thousands place go up one

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If tan Θ = 1 2 then what is sin Θ?
diamong [38]
Tanx=85

Sin85=0.100

I hope my answer will be helpful to you
7 0
4 years ago
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If there are 6 grams of tea leaves to make 24 fluid ounces of tea last week she made 288 fluid ounces of tea how many grams of t
NikAS [45]
72 grams! 6 grams = 24 fluid ounces. Thats exactly 1/4. So what you would do is take 288 and divide by 4 and you would get 72 grams!
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4 years ago
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Help please thanks math is hard
leonid [27]
X= 25
Explanation:
The two lines are equal. Since 48+16= 64,
the other line has to equal 64 as well.
64-39= 25
8 0
3 years ago
Can someone pls do these quick
balu736 [363]

Answer:

6. x° is approximately 21.04°

7. x° is approximately 39.56°

8. x° is approximately 58.03°

9. x° is approximately 72.85°

Step-by-step explanation:

6. In the given right triangle (a triangle with the measure of one of the interior angles equal to 90°, indicated by the small square between two sides) , we have;

The hypotenuse side length = 15

The adjacent side to the given reference angle, x° = 14

By trigonometric ratio, we have;

cos\angle X = \dfrac{Adjacent\ leg \ length}{Hypotenuse \ length}

\therefore cos(x^{\circ}) = \dfrac{14}{15}

To find the value of x°, we make use of the inverse cosine function, arccos found on a scientific calculator, as follows;

x° = arccos(14/15) ≈ 21.04°

x° ≈ 21.04°

7. In the given right triangle, we have;

The length of the opposite side to the given reference angle, x° = 19

The length of the adjacent side to the given reference angle, x° = 23

By trigonometric ratios, we have;

Tan(\angle X) = \dfrac{Opposite \, side \  length}{Adjacent\, side \ length}

\therefore tan(x^{\circ}) =  \dfrac{19}{23}

Therefore;

x° = arctan(19/23) ≈ 39.56°

x° ≈ 39.56°

8. In the given right triangle, the adjacent side to the reference angle, x° and the hypotenuse side are given, therefore, we have;

x° = arccos(9/17) ≈ 58.03°

x° ≈ 58.03°

9. The opposite side to the reference angle and the hypotenuse side are given

By trigonometric ratio, we have;

sin\angle X = \dfrac{Opposite \ leg \ length}{Hypotenuse \ length}

\therefore sin(x^{\circ}) = \dfrac{43}{45}

x° = arcsin(43/45) ≈ 72.85°

x° ≈ 72.85°.

6 0
3 years ago
Find a cubic polynomial whose graph passes through the points (1,3),(2,−2),(3,−5),(4,0)
scoundrel [369]
The generic equation of a third degree polynomial is given by:
 y = ax ^ 3 + bx ^ 2 + cx + d
 We must make a system of equations to find the values of a, b, c, d.
 We have then:
 For (1, 3):
 3 = a (1) ^ 3 + b (1) ^ 2 + c (1) + d
 3 = a + b + c + d
 For (2, -2):
 -2 = a (2) ^ 3 + b (2) ^ 2 + c (2) + d
 -2 = 8a + 4b + 2c + d
 For (3, -5):
 
-5 = a (3) ^ 3 + b (3) ^ 2 + c (3) + d
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 For (4.0):
 0 = a (4) ^ 3 + b (4) ^ 2 + c (4) + d
 0 = 64a + 16b + 4c + d
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 3 = a + b + c + d
 -2 = 8a + 4b + 2c + d
 -5 = 27a + 9b + 3c + d
 0 = 64a + 16b + 4c + d
 Whose solution is:
 a = 1
 b = -5
 c = 3
 d = 4
 The polynomial will then be:
 y = x ^ 3 - 5x ^ 2 + 3x + 4
 Answer:
 
y = x ^ 3 - 5x ^ 2 + 3x + 4
4 0
3 years ago
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