What is 121,580 rounded to the nearest thousand
1 answer:
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Answer with Step-by-step explanation:
We are given that a sample space
S={a,b,c,d,e}
P(a)=0.1
P(b)=0.1
P(c)=0.2
P(d)=0.4
P(e)=0.2
a.A={a,b,c}
P(A)=P(a)+P(b)+P(c)
P(A)=0.1+0.1+0.2=0.4
b.B={c,d,e}
P(B)=P(c)+P(d)+P(e)=0.2+0.4+0.2=0.8
c.A'=Sample space-A={a,b,c,d,e}-{a,b,c}={d,e}
P(A')=P(d)+P(e)=0.4+0.2=0.6
d.={a,b,c,d,e}
=P(a)+P(b)+P(c)+P(d)+P(e)=0.1+0.1+0.2+0.4+0.2=1
e.={c}
For this case we have that by definition, a linear function is of the form
We have the following options:
A)
Rewriting:
It's a quadratic function!
B)
Rewriting:
It's a linear function!
C)
Rewriting:
It's a cubic function.
D)
Rewriting:
It's a quadratic function!
E)
Rewriting:
It's a cubic function!
Answer:
The linear function is option B