Answer with Step-by-step explanation:
We are given that a sample space
S={a,b,c,d,e}
P(a)=0.1
P(b)=0.1
P(c)=0.2
P(d)=0.4
P(e)=0.2
a.A={a,b,c}
P(A)=P(a)+P(b)+P(c)
P(A)=0.1+0.1+0.2=0.4
b.B={c,d,e}
P(B)=P(c)+P(d)+P(e)=0.2+0.4+0.2=0.8
c.A'=Sample space-A={a,b,c,d,e}-{a,b,c}={d,e}
P(A')=P(d)+P(e)=0.4+0.2=0.6
d.
={a,b,c,d,e}
=P(a)+P(b)+P(c)+P(d)+P(e)=0.1+0.1+0.2+0.4+0.2=1
e.
={c}

For this case we have that by definition, a linear function is of the form

We have the following options:
A) 
Rewriting:

It's a quadratic function!
B) 
Rewriting:

It's a linear function!
C)
Rewriting:

It's a cubic function.
D) 
Rewriting:

It's a quadratic function!
E)
Rewriting:

It's a cubic function!
Answer:
The linear function is option B
{4x + 4y = 20 | ÷4<span>
{2x -2y = -18 | </span>÷2
{x + y = 5
{x -y = -9
--------------
2x = -4
x = -2
x + y = 5
-2 + y = 5
y = 5 + 2
y = 7
The answer is (-2, 7)
Work = Force * distance (along the line of force)
= 20N*10m
=200 N-m
=200 joules