Answer:
Step-by-step explanation:
![6k^3+10k^2-56k\\2k(3k^2+5k-28)\\=2k[3k^2+12k-7k-28]\\=2k[3k(k+4)-7(k+4)]\\=2k(k+4)(3k-7)](https://tex.z-dn.net/?f=6k%5E3%2B10k%5E2-56k%5C%5C2k%283k%5E2%2B5k-28%29%5C%5C%3D2k%5B3k%5E2%2B12k-7k-28%5D%5C%5C%3D2k%5B3k%28k%2B4%29-7%28k%2B4%29%5D%5C%5C%3D2k%28k%2B4%29%283k-7%29)
common factor is 3k-7
Answer:
11.7 units
Step-by-step explanation:
sq root(2--4)^2+(-7-3)^2
sq root(6)^2 + (-10)^2
sq root (36)+(100)
sq root 136
equals 11.66 which rounds up to 11.7
From the given diagram <msr is a right angle (equal to 90 degrees) and <mrh is acute since it is less than 90degrees.
<h3>Properties ofa rhombus</h3>
The given diagram is a rhombus that has the following properties
- Opposite side are equal
- All the sides are congruent
- The opposite angles are equal
- The sum of the adjacent angles are supplementary
From the figure shown, we can see that;
<msr is a right angle (equal to 90 degrees)
<mrh is acute since it is less than 90degrees.
Learn more on rhombus here: brainly.com/question/88523
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