Instead of using the quotient rule, you can first expand <em>y</em> :
<em>y</em> = (4<em>x</em> - 1)^2 / <em>x</em> ^2 = (16<em>x</em> ^2 - 8<em>x</em> + 1) / <em>x</em> ^2 = 16 - 8/<em>x</em> + 1/<em>x</em> ^2
Then the derivative is
d<em>y</em>/d<em>x</em> = -8/<em>x</em> ^2 - 2/<em>x</em> ^3
The tangent to the curve at (-1, 25) then has a slope or gradient of
d<em>y</em>/d<em>x</em> = -8/(-1)^2 - 2/(-1)^3 = -6
Step-by-step explanation:
for a perpendicular,
make x the subject.
8x=11-3y
x=11/8 +3/8
for a perpendicular, the gradient
x= -1/m
x= (-1/11/8) - (-1/3y/8)
x= 8/3y -8/11.
therefore the gradient (m) = 8/3y -8/11.
A. -3/7 = -0.4286
b. -5/6 = -0.8333
c. -3/5 = -0.6000
d. -7/9 = -0.7777
bdca is least to greatest
Correct answer is D.
Answer:
= 105
Step-by-step explanation:
