I think B and the second one C
Answer:
- equation = input("Enter an equation: ")
-
- if("+" in equation):
- operands = equation.split("+")
- result = int(operands [0]) + int(operands[1])
- print(operands[0] + "+" + operands[1] + "=" + str(result))
- elif("-" in equation):
- operands = equation.split("-")
- result= int(operands [0]) - int(operands[1])
- print(operands[0] + "-" + operands[1] + "=" + str(result))
- elif("*" in equation):
- operands = equation.split("*")
- result = int(operands [0]) * int(operands[1])
- print(operands[0] + "*" + operands[1] + "=" + str(result))
- elif("/" in equation):
- operands = equation.split("/")
- result = int(operands [0]) / int(operands[1])
- print(operands[0] + "/" + operands[1] + "=" + str(result))
- elif("%" in equation):
- operands = equation.split("%")
- result = int(operands [0]) % int(operands[1])
- print(operands[0] + "%" + operands[1] + "=" + str(result))
Explanation:
The solution code is written in Python 3.
Firstly prompt user to enter an equation using input function (Line 1).
Create if-else if statements to check if operator "+", "-", "*", "/" and "%" exist in the input equation. If "+" is found (Line 3), use split method to get the individual operands from the equation by using "+" as separator (Line 5). Output the equation as required by the question using string concatenation method (Line 6). The similar process is repeated for the rest of else if blocks (Line 7 - 22).
Answer:
I personally use a alienware
Explanation:
Answer:
ranforce = randi([0, 12]);
if (ranforce == 0)
disp('There is no wind')
else if(ranforce>0 && ranforce <7)
disp('There is a breeze')
else if(ranforce>6 && ranforce <10)
disp('This is a gale')
else if(ranforce>9 && ranforce <12)
disp('It is a storm')
else if(ranforce==12)
disp('Hello, Hurricane!')
end
Explanation:
<em>Replace all switch case statements with if and else if statements.</em>
<em>An instance is:</em>
<em>case {7,8,9}</em>
<em>is replaced with</em>
<em>else if(ranforce>9 && ranforce <12)</em>
<em>All other disp statements remain unchanged</em>
