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3 years ago

What is the output of this program?

Computers and Technology

2 answers:

cupoosta [38]3 years ago

4 0

Answer:

The output is 20

Explanation:

Given:

numA = 2

for count in range(5,8):

numA = numA + count

print(numA)

Required:

Determine the output

The first line of the program initializes numA to 2.

The next iteration sum up integers from 5 to 7 (i.e. 8 - 1) to the initialized value of numA

So, numA becomes

$numA = 2 + 5 + 6 + 7$

$numA = 20$

Hence, the output is 20

Charra [1.4K]3 years ago

3 0

Answer:

Explanation:

assuming the print statement is not indented, the program effectively calculates 2+5+6+7.

The range(...) is excluding the end value (8 in this case).

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4 years ago

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Vladimir79 [104]

Answer:

Explanation:

//Include the required header files.

#include<iostream>

using namespace std;

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{

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char ch;

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}

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cout << "\n\nThe sum of the even numbers is:"

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cout << "The sum of squares the odd numbers is:"

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i = 1;

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system("pause");

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Explanation:

The program code will perform the function listed below using loop.

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