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Gennadij [26K]
1 year ago
13

A student has a savings account earning 3% simple interest. She must pay $1200 for first-semester tuition by September 1 and $12

00 for second-semester tuition by January 1. How
much must she earn in the summer (by September 1) to pay the first-semester bill on time and still have the remainder of her summer earnings grow to $1200 between September 1
and January 1? (Round your answer to the nearest cent.)
Mathematics
1 answer:
Bingel [31]1 year ago
3 0

Using simple interest, it is found that she needs to earn $2,391.07 during the summer.

<h3>Simple Interest</h3>

Simple interest is used when there is a single compounding per time period.

The amount of money after t years in is modeled by:

A(t) = A(0)(1 + rt)

In which:

  • A(0) is the initial amount.
  • r is the interest rate, as a decimal.

For this problem, the objective is to have <u>$1200 in 3 months = 0.25 years</u>, hence the parameters are given as follows:

A(0.25) = 1200, t = 0.25, r = 0.03.

Hence we have to solve for A(0):

A(0)(1 + 0.03 x 0.25) = 1200

A(0) = 1200/(1 + 0.03 x 0.25)

A(0) = $1,191.07.

She also needs to earn $1,200 to pay the first-semester bill on time, hence:

1200 + 1191.07 = $2,391.07.

She needs to earn $2,391.07 during the summer.

More can be learned about simple interest at brainly.com/question/16646150

#SPJ1

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This is an incomplete question, here is a complete question and image is also attached below.

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Step-by-step explanation:

Using Pythagoras theorem in ΔACB :

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Now put all the values in the above expression, we get the value of side AB.

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AB=\sqrt{(6)^2+(8)^2}

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Now we have to calculate the how much longer is the hypotenuse of the triangle than its shorter leg.

Difference = Side AB - Side AC

Difference = 10 ft - 6 ft

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