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Gennadij [26K]
1 year ago
13

A student has a savings account earning 3% simple interest. She must pay $1200 for first-semester tuition by September 1 and $12

00 for second-semester tuition by January 1. How
much must she earn in the summer (by September 1) to pay the first-semester bill on time and still have the remainder of her summer earnings grow to $1200 between September 1
and January 1? (Round your answer to the nearest cent.)
Mathematics
1 answer:
Bingel [31]1 year ago
3 0

Using simple interest, it is found that she needs to earn $2,391.07 during the summer.

<h3>Simple Interest</h3>

Simple interest is used when there is a single compounding per time period.

The amount of money after t years in is modeled by:

A(t) = A(0)(1 + rt)

In which:

  • A(0) is the initial amount.
  • r is the interest rate, as a decimal.

For this problem, the objective is to have <u>$1200 in 3 months = 0.25 years</u>, hence the parameters are given as follows:

A(0.25) = 1200, t = 0.25, r = 0.03.

Hence we have to solve for A(0):

A(0)(1 + 0.03 x 0.25) = 1200

A(0) = 1200/(1 + 0.03 x 0.25)

A(0) = $1,191.07.

She also needs to earn $1,200 to pay the first-semester bill on time, hence:

1200 + 1191.07 = $2,391.07.

She needs to earn $2,391.07 during the summer.

More can be learned about simple interest at brainly.com/question/16646150

#SPJ1

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The answer is given below

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the​ oil-change facility will perform 45 oil changes between 10 A.M. and 12 P.M, therefore the sample size n = 45

there be a​ 10% chance of being at or​ below. From the normal distribution table, The z score corresponding to a probability of 10% (= 0.1)  is -1.28.

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To calculate the mean​ oil-change time, we use the formula:

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Answer:

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Step-by-step explanation:

Let the portion of the wall painted by Jiaqi, Gwen and Patricia be denoted as X, Y and Z respectively.

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Patricia (Z):

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Area of the wall painted:

Let the area of the wall painted by Gwen and Patricia be Y + Z.

The area painted by Jiaqi = 2/5 + Y + Z

Therefore,

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Total units, 14 units = 28/25

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