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Otrada [13]
3 years ago
12

Solving polynomial(2y-4)(3y+6)​

Mathematics
2 answers:
Soloha48 [4]3 years ago
6 0

\Large{ \boxed{ \rm{ \red{To \: solve?}}}}

  • (2y - 4)(3y + 6)
<h3><u>Solution</u><u>:</u><u>-</u></h3>

⇛ (2y - 4)(3y + 6)

⇛ 2y(3y + 6) - 4(3y + 6)

⇛ 6y² + 12y - 12y - 24

⇛ 6y² - 24

☃️ <u>So</u><u>,</u><u> </u><u>Final</u><u> </u><u>answer</u><u> </u><u>=</u><u> </u><u>6y</u><u>²</u><u> </u><u>-</u><u> </u><u>2</u><u>4</u>

jeka57 [31]3 years ago
3 0

Answer:

6y² - 24

Step-by-step explanation:

Expand. Follow FOIL method. FOIL =

First

Outside

Inside

Last.

First, multiply the first term of each parenthesis:

2y * 3y = 6y²

Next, multiply the outside terms from both parenthesis:

2y * 6 = 12y

Then, multiply the inside terms from both parenthesis:

-4 * 3y = -12y

Finally, multiply the last terms of each parenthesis:

-4 * 6 = -24

Combine like terms:

6y² + 12y - 12y - 24

6y² + (12y - 12y) - 24

6y² - 24

6y² - 24 is your answer.

~

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