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3 years ago

In spherical geometry, what is the term used for the shortest distance between two points?

1 answer:

3 0

The correct answer for the question shown above is: Geodesic.

The explanation of is shown below:
1. You have that ,by definition, the spherical geometry studies figures on the surface of the spheres.
2. And the termn known as "Geodesic" is define as <span>the shortest distance between two points on the surface of a sphere or a curved surface. </span>

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Find the solution to the system of equations below (you can do this by substitution or elimination).

rewona [7]

Step-by-step explanation:

y=6+4x, as equation (iii)

=> -5x-(6+4x)=21

=> -5x-6-4x=21

=> -5x-4x-6=21

=> -9x-6=21

=> -9x=21+6

=> -9x=27

x= -3, by dividing both sides by -9

So, by inserting x in the first equation,

=> -4(-3)+y=6

=> 12+y=6

=> y=6-12

=> y= -6.

Therefore, x= -3 and y= -6

8 0

2 years ago

How many three-fourths are in 2

Elis [28]

3/4 times x=2
times both sides by 4/3 to clear fraction (4/3 times 3/4=12/12=1)
1x=8/3
there are 8/3 of them in 2

6 0

2 years ago

Read 2 more answers

This is due by 7pm i need help

Ad libitum [116K]

Answer:

bruh u need a link

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

SAT scores are normed so that, in any year, the mean of the verbal or math test should be 500 and the standard deviation 100. as

vovangra [49]

Answer:

a) $P(X>625)=P(\frac{X-\mu}{\sigma}>\frac{625-\mu}{\sigma})=P(Z>\frac{625-500}{100})=P(Z>1.25)$

$P(Z>1.25)=1-P(Z$

b) $P(400$

$P(-1$

c) $z=-0.842$

And if we solve for a we got

$a=500 -0.842*100=415.8$

So the value of height that separates the bottom 20% of data from the top 80% is 415.8.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the SAT scores of a population, and for this case we know the distribution for X is given by:

$X \sim N(500,100)$

Where $\mu=500$ and $\sigma=100$

We are interested on this probability

$P(X>625)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>625)=P(\frac{X-\mu}{\sigma}>\frac{625-\mu}{\sigma})=P(Z>\frac{625-500}{100})=P(Z>1.25)$

And we can find this probability using the complement rule and with the normal standard table or excel:

$P(Z>1.25)=1-P(Z$

Part b

We are interested on this probability

$P(400$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(400$

And we can find this probability with this difference:

$P(-1$

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

$P(-1$

Part c

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.8$ (a)

$P(X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.2 of the area on the left and 0.8 of the area on the right it's z=-0.842. On this case P(Z<-0.842)=0.2 and P(Z>-0.842)=0.8

If we use condition (b) from previous we have this:

$P(X$