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3 years ago

Helppppppppppppppppppp

Mathematics

1 answer:

DochEvi [55]3 years ago

7 0

Angle 2 and angle 11 are alternate exterior angles. Line G and line L are parallel lines. Think of them as train tracks. On the outside or exterior of the train tracks is angle 2 and angle 11.

Angle 2 is on the right side of the transversal line, while angle 11 is on the left side of the transversal line.

So this is why they are alternate exterior angles. Because line G and line L are parallel lines, this means the alternate exterior angles are congruent (by the alternate exterior angle theorem).

Since angle 2 is 115 degrees, angle 11 must also be 115 degrees

Answer: C) 115

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4 years ago

What is 1/3 equal too

sattari [20]

The numerator in a fraction represents the number of pieces selected. If the numerator is larger than the denominator, the number is larger than one

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3 years ago

Find the product (8/6n-4)(9n^2-4)

Leokris [45]

Answer:

4(3n+2) or 12n+8

Step-by-step explanation:

Given expression is:

$(\frac{8}{6n-4})(9n^{2}-4)$

The numerator of the fraction will be multiplied with 9n^2- 4

So, Multiplication will give us:

$=\frac{8(9n^2-4)}{6n-4}$

We can simplify the expression before multiplication.

The numerator will be broken down using the formula:

$a^2 - b^2 = (a+b)(a-b)\\So,\\= \frac{8[(3n)^2 - (2)^2]}{6n-4}\\ = \frac{8(3n-2)(3n+2)}{6n-4}$

We can take 2 as common factor from denominator

$=\frac{8(3n-2)(3n+2)}{2(3n-2)}\\After\ cutting\\= 4(3n+2)$

Hence the product is 4(3n+2) or 12n+8 ..

6 0

3 years ago

The length of a rectangle is increasing at a rate of 4 meters per day and the width is increasing at a rate of 1 meter per day.

puteri [66]

Answer:

$\displaystyle \frac{dA}{dt} = 102 \ m^2/day$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Geometry

Area of a Rectangle: A = lw

l is length
w is width

Calculus

Derivatives

Derivative Notation

Implicit Differentiation

Differentiation with respect to time

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

$\displaystyle l = 10 \ meters$

$\displaystyle \frac{dl}{dt} = 4 \ m/day$

$\displaystyle w = 23 \ meters$

$\displaystyle \frac{dw}{dt} = 1 \ m/day$

Step 2: Differentiate

[Area of Rectangle] Product Rule: $\displaystyle \frac{dA}{dt} = l\frac{dw}{dt} + w\frac{dl}{dt}$

Step 3: Solve

[Rate] Substitute in variables [Derivative]: $\displaystyle \frac{dA}{dt} = (10 \ m)(1 \ m/day) + (23 \ m)(4 \ m/day)$
[Rate] Multiply: $\displaystyle \frac{dA}{dt} = 10 \ m^2/day + 92 \ m^2/day$
[Rate] Add: $\displaystyle \frac{dA}{dt} = 102 \ m^2/day$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Implicit Differentiation

Book: College Calculus 10e

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3 years ago

6 mi Find the volume for the shape above. Use 3.14 for pi. Round to the nearest whole number.

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Answer:

Step-by-step explanation: does anyone know? I really need this

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3 years ago