3
the area is 41.6cm which is 1foot 4 3/8 inches.
So 6in + 6in + 6in = 1ft 6in, which will be enough to cover the floor.
Answer:
A = 139.25
Step-by-step explanation:
I think the scale factor of one block to the arrangement would be 1/9, since the arrangement contains 9 blocks.
So if the length at the top is 12 cm, the length of the bottom of a trapezoid would be 12(1/9) = 4/3
Since we know that each trapezoid holds 3 equilateral triangles, the length of each side and the top of the trapezoidal would be 4/3 x 1/2 = 2/3 cm
The sum of the angles must equal 360 degrees, and because they are made of equilateral triangles, you know that each angle of the triangle must be 60 degrees. So the bottom two angles of the trapezoid are each 60 degrees, and the top two are 360- 120 = 240 divided by 2 angles = 120 degrees each.
Answer:
The six trig ratios at 3pi/2 are:
sin(3pi/2)=-1
cos(3pi/2)=0
tan(3pi/2) (undefined)
csc(3pi/2)=-1
sec(3pi/2) (undefined)
cot(3pi/2)=0
Step-by-step explanation:
If tangent is undefined then cosine would have to be 0 given that tangent is the ratio of sine to cosine.
cosine is 0 at pi/2 and 3pi/2 in the first rotation of the unit circle.
3pi/2 satisfies the given constraint.
The six trig ratios are therefore:
sin(3pi/2)=-1
cos(3pi/2)=0
tan(3pi/2)=-1/0 (undefined)
Reciprocal values:
csc(3pi/2)=-1
sec(3pi/2) undefined since cos(3pi/2)=0
cot(3pi/2)=0/-1=0
Answer:
p = 16
Step-by-step explanation:
Given p is directly proportional to (q + 2)² then the equation relating them is
p = k(q + 2)² ← k is the constant of proportion
To find k use the condition when q = 1, p = 1
1 = k(1 + 2)² = k × 3² = 9k ( divide both sides by 9 )
= k
p = (q + 2)² ← equation of proportion
When q = 10 , then
p = × (10 + 2)² = × 12² = × 144 = 16
