Answer:
B , D , A ,C
Step-by-step explanation:
PEMDAS
Hey there!
<u>Solve </u><u>the </u><u>equation</u><u>:</u>
c = 7 ✅
2c + 3 = 3c - 4
<em>></em><em>></em><em> </em><em>Subtract </em><em>3</em><em> </em><em>from </em><em>both </em><em>sides </em><em>:</em>
<em> </em>
2c + 3 - 3 = 3c - 4 - 3
2c = 3c - 7
<em>></em><em>></em><em> </em><em>Substrat </em><em>3</em><em>c</em><em> </em><em>from </em><em>both </em><em>sides </em><em>:</em>
2c - 3c = 3c - 7 - 3c
-c = -7
<em>></em><em>></em><em> </em><em>Divide</em><em> </em><em>each </em><em>side </em><em>by </em><em>-</em><em>1</em><em> </em><em>:</em>
-c / -1 = -7 / -1
c = 7
2c + 3 ⇔ 2(7) + 3 ⇔ 14 + 3 ⇔ 17
3c - 4 ⇔ 3(7) - 4 ⇔ 21 - 4 ⇔ 17
Therefore, your answer is c = 7 .
Mor about equation :
brainly.com/question/27353929
Have a good day :)
Answer:
![\text{c) }\sqrt[4]{64}=2\sqrt[4]{4}](https://tex.z-dn.net/?f=%5Ctext%7Bc%29%20%7D%5Csqrt%5B4%5D%7B64%7D%3D2%5Csqrt%5B4%5D%7B4%7D)
Step-by-step explanation:
![\text{a) }64\qquad\text{an integer; not a surd}\\\\\text{b) }\sqrt[6]{64}=2\qquad\text{an integer; not a surd}\\\\\text{c) }\sqrt[4]{64}=2\sqrt[4]{4}\qquad\textbf{a surd}\\\\\text{d) }\sqrt[3]{64}=4\qquad\text{an integer; not a surd}](https://tex.z-dn.net/?f=%5Ctext%7Ba%29%20%7D64%5Cqquad%5Ctext%7Ban%20integer%3B%20not%20a%20surd%7D%5C%5C%5C%5C%5Ctext%7Bb%29%20%7D%5Csqrt%5B6%5D%7B64%7D%3D2%5Cqquad%5Ctext%7Ban%20integer%3B%20not%20a%20surd%7D%5C%5C%5C%5C%5Ctext%7Bc%29%20%7D%5Csqrt%5B4%5D%7B64%7D%3D2%5Csqrt%5B4%5D%7B4%7D%5Cqquad%5Ctextbf%7Ba%20surd%7D%5C%5C%5C%5C%5Ctext%7Bd%29%20%7D%5Csqrt%5B3%5D%7B64%7D%3D4%5Cqquad%5Ctext%7Ban%20integer%3B%20not%20a%20surd%7D)
Answer:
d.
Step-by-step explanation:
i looked at the graph!
