Diana read 6 English books and 32 French books in 1996.
For given question,
Let the number of English books = x
And the number of French books = y
In 1995 Diana read 10 English books and 7 French books.
⇒ x = 10 and y = 7
In 1996, she read twice as many French books as English books.
So, we get an equation,
⇒ y = 2x
Also, 60% of the books that she read during the 2 years were French
Let m be the total number of books she read in 2 years.
⇒ y = 60 percent of m
⇒ y = 0.6(m) ............(i)
and x = 0.4(m)
We don't know the exact amount of books read in 1996.
m = 10 + 7 +x +2x
m = 17 + 3x
We can write equation (i) as,
⇒ 0.6(m) = 7 + 2x
⇒ 0.6(17 + 3x) = 7 + 2x
⇒ 10.2 + 1.8x = 7 + 2x
⇒ 10.2 - 7 = 2x - 1.8x
⇒ 3.2 = 0.2x
⇒ 3.2/0.2 = x
⇒ 16 = x
So, she read 16 English books
And 16 × 2 = 32 French books
Total books: 16+32= 48 books in 1996
Therefore, Diana read 6 English books and 32 French books in 1996.
Learn more about an equation here:
brainly.com/question/649785
#SPJ4
