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Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
Answer:
The weight of large and small box are 18.25 kg and 13.25 kg respectively.
Step-by-step explanation:
Let the weight of large and small box are x and y respectively.
It is given that a delivery of 5 large boxes and 3 small boxes has a total weight of 131 kilograms.
.... (1)
A delivery of 2 large boxes and 6 small boxes has a total weight of 116 kilograms.
.... (2)
On solving (1) and (2) using graphing calculator, we get
Therefore the weight of large and small box are 18.25 kg and 13.25 kg respectively.
X = k/p^3
125 = k/10^3 = k/1000
1000 x 125 = k
k = 125000
x = 125000/p^3
The profit is given by G = px - (125 + 2x) = p(125000/p^3) - 125 - 2(125000/p^3) = 125000/p^2 - 250000/p^3 - 125
For maximum profit:
dG/dp = 0
dG/dp = -250000/p^3 + 750000/p^4 = 0
750000 - 250000p = 0
p = 750000/250000 = 3
Therefore the price that will yeaild maximum profit is $3.
It's A.
All you need to do is plug in the X from the ordered pair, then solve.
y=-5x-4
y=-5(10)-4
y=-50-4
y=-54
Which is NOT -52, so the answer is indeed A
Options
A. The number of cars passing through the intersection in one hour
B. The number of pedestrians crossing the intersection in one hour
C. The number of bicyclists crossing the intersection in one hour
D. The number of food trucks that park within four blocks of the intersection
E. The number of minutes for a car to get from the intersection to the administration building
Answer:
The number of minutes for a car to get from the intersection to the administration building
Step-by-step explanation:
A variable is said to be discrete if and only if it has a countable number of values. While a variable is said to be continuous if it can take infinitely many values.
Option a to d contains discrete variables (1 hour) and (4 blocks), so they can't be regarded as the right option. 1 hour and 4 blocks are specified values and they can't take any other fraction of values aside 1 and 4 respectively.
Looking at option e, the variable, number of minute as stated in this option is a continuous variable. This is so because at any two interval of minutes, fractions and lots of a minute can always be recorded by the engineer to study the traffic flow
