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yulyashka [42]
3 years ago
14

Quadrilateral ABCD is inscribed in circle as shown. What is the value of y?

Mathematics
1 answer:
julsineya [31]3 years ago
7 0
The value of y is 83 degrees because any quadrilaterals opposite sides or angles are equal and opposite (or diagonal) from point D.

Hope this helps !
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Please help!!! I don't understand how this works.
frosja888 [35]

Answer:

Step-by-step explanation:

64,000 x 6.2% divided by groups of 1.45 a

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What’s the question LOLOL.
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PLSS HELPP QHEJJEWJAKWK<br><br><br> What is the vertex of the parabola in the graph?
vesna_86 [32]

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(-3,-4)

Step-by-step explanation:

The vertex is the minimum or maximum or a parabola.

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Andre45 [30]
<h3>Answer: The average rate of change for both is -2</h3>

=======================================================

Explanation:

The x interval [0,3] is the same as writing 0 \le x \le 3

It starts at x = 0 and ends at x = 3.

The graph shows that x = 0 leads to y = 3. So we have the point (0,3) on the parabola. We also have the point (3,-3) on the parabola.

Let's find the slope of the line through these endpoints.

(x_1,y_1) = (0,3) \text{ and } (x_2,y_2)  = (3,-3)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{-3 - 3}{3 - 0}\\\\m = \frac{-6}{3}\\\\m = -2\\\\

The slope is -2. This is the average rate of change from x = 0 to x = 3.

This is because:

slope = rise/run = (change in y)/(change in x) = average rate of change.

-------------

Now let's find the slope for the table.

Focus on the rows for x = 0 and x = 3. They lead to f(x) = 10 and f(x) = 4 respectively.

We have (0,10) and (3,4) as our two points this time.

(x_1,y_1) = (0,10) \text{ and } (x_2,y_2)  = (3,4)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{4 - 10}{3 - 0}\\\\m = \frac{-6}{3}\\\\m = -2\\\\

We get the same slope as before, so we have the same rate of change.

Notice the change in y (-6) is the same as before. So we could pick any two y values we want as long as there's a gap of 6 between them, and the second y value is smaller than the first.

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2 years ago
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