Answer:
x^4- x^3- 4x^2-3
Step-by-step explanation:
Given
f(x)= x^4- x^2+9
And
g(x)= x^(3 )+ 3x^2+12
We have to find
(f-g)(x)= ?
The operations on functions are as easy as the operations on numbers or polynomials.
We have to subtract the functions to find the above mentioned operation.
=(f-g)(x)=f(x)-g(x)
(f-g)(x)=[x^4- x^2+9]-[x^(3 )+ 3x^2+12]
The minus will change the signs of function g.
= x^4- x^2+9- x^(3 )- 3x^2-12
= x^4- x^3- x^2- 3x^2+9-12
=x^4- x^3- 4x^2-3
Answer:
y - 12 = 9(x - 4)
Step-by-step explanation:
The vertex (h, k) is (4, 12) and the point (5, 21) is on the graph. Assuming that this is a vertical parabola, opening up (because the coordinate 21 is greater than the coordinate 12), we insert the knowns into y - k = a(x - h)^2, obtaining
21 - 12 = a(5 - 4), or 9 = a. With a known, we can write the desired equation:
y - 12 = 9(x - 4)
Can you be more specific pls
Since both statements are true, then it is
contrapositive
