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4 years ago

15

A number decreased by 12 is 24.

2 answers:

igomit [66]4 years ago

7 0

A number decreased by 12 is 24...
n - 12 = 24
n = 24 + 12
n = 36 <== ur number

Galina-37 [17]4 years ago

3 0

A number decreased by 12 is 24.
(by looking at your question, we can see that 'decreased by 12' = subtract (-) 12)

We can write this as the equation n - 12 = 24, in which n = the number.

Now let's solve for n by using algebraic properties.

n - 12 = 24
n - 12 + 12 = 24 + 12 (add 12 to both sides to isolate n)
n = 24 + 12 (the -12 and +12 cancel to 0 on the left side)
n = 36 (simplify, add 24 and 12)

Therefore the number is 36.

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3 years ago

Please explain how to solve the problem.

EastWind [94]

Answer:

Part 1) $f(125)=6$

Part 2) $f(-64)=-3$

Step-by-step explanation:

we have

$f(x)=\sqrt[3]{x} +1$

Part 1) Find f(125)

we know that

f(125) is the value of the function f(x) when the value of x is equal to 125

so

For x=125

substitute in the function

$f(125)=\sqrt[3]{125} +1$

Remember that

$125=5^{3}$

substitute

$f(125)=\sqrt[3]{5^{3}} +1$

Applying the power of rule

$\sqrt[3]{5^{3}}=(5^{3})^{\frac{1}{3}}= (5)^{3*\frac{1}{3}}=5$

substitute

$f(125)=5 +1=6$

Part 2) Find f(-64)

we know that

f(-64) is the value of the function f(x) when the value of x is equal to -64

so

For x=-64

substitute in the function

$f(-64)=\sqrt[3]{-64} +1$

Remember that

$-64=-4^{3}$

substitute

$f(-64)=\sqrt[3]{-4^{3}} +1$

Applying the power of rule

$\sqrt[3]{-4^{3}}=(-4^{3})^{\frac{1}{3}}= (-4)^{3*\frac{1}{3}}=-4$

substitute

$f(-64)=-4 +1=-3$

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4 years ago

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Answer:

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B: -185/18

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3 years ago

Read 2 more answers