a) if the two gloves someone receives might both be for the left hand or right hand.
b) if each sister gets one left and one right.
Soln:
a) So i thought about dissectng the problem first into finding the number of ways in which I could make pairs of gloves:
C(12, 2)
then I asked how many ways could the sets of gloves be assigned amongst the 6 sisters:
<span><span>6!</span><span>6!</span></span>
and taking the product of this would give me the amount of ways this could occur:
= C(12,2) * 6!
then for part b)
using this same idea except:
C(6,1) C(6,1) for the left and right glove each .
the C(6,1)*C(6,1)*6!
Right way to think them through?
Answer:
39-6a
Step-by-step explanation:
(4 - a) - 5(a - 7) Distribute the -5 throughout (a-7)
4 - a - 5a + 35 Combine like terms
4 + 35 - a - 5a
39 - 6a
Answer:
10
Step-by-step explanation:
Answer:
Step-by-step explanation:
57-2=55
55+7=62
it does not equal 111
3k-1=7k+2
+1 +1
3k=7k+3
-7k -7k
-4k=3
divide each side by -4
/-4 /-4
k=-3/4
or
k=-.75