Answer:
#2
#3
Step-by-step explanation:
Can I have brainilest plz
<em>AC bisects ∠BAD, => ∠BAC=∠CAD ..... (1)</em>
<em>thus in ΔABC and ΔADC, ∠ABC=∠ADC (given), </em>
<em> ∠BAC=∠CAD [from (1)],</em>
<em>AC (opposite side side of ∠ABC) = AC (opposite side side of ∠ADC), the common side between ΔABC and ΔADC</em>
<em>Hence, by AAS axiom, ΔABC ≅ ΔADC,</em>
<em>Therefore, BC (opposite side side of ∠BAC) = DC (opposite side side of ∠CAD), since (1)</em>
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Hence, BC=DC proved.
Question #25:
One way to solve this is by multiplying the number of packages per serving by the number of guests.
1/4 * 16 = 4 packages to serve 16 guests. This means he doesn't have enough.
A second way to solve this is by diving the number of packages by the number of packages it takes to make on serving.
3 1/2 ÷ 1/4 = 14 guests he can serve. This means he doesn't have enough.
Question #26:
First, find common denominators.
2/3 = 8/12
1/4 = 3/12
Second, subtract.
8/12 - 3/12 = 5/12
Therefore, the tank is 5/12 full at the end of the trip.
Question #27:
1/2 is cut off then 1/3 is cut off. This means 3/6 was cut off to bundle newspapers, then 1/6 was cut off to make parcel. In all, 4/6 was cut off the original string. Afterwards, 2/6 was left over. So, just multiply; 2 * 3 = 6.
Therefore, the original string was as a total of 6 meters.
Best of Luck!
H(x) equals what? I think you've missed that detail. :)