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3 years ago

A line passes through the point (-2,7) and had a slope of -5

Mathematics

2 answers:

saw5 [17]3 years ago

8 0

Answer:

b. -1

Step-by-step explanation:

you find the point and then go down 5 vertically within one horizontally to show the -5 slope and it will leave you at (-1, 2)

Annette [7]3 years ago

7 0

Answer:

a = -1

Step-by-step explanation:

The general equation for a straight line is y = mx+c, where m is the gradient/ slope, so m = -5. The first thing we need to do is find c, which we do by plugging in the x and y values that we already know: y = 7 and x = -2

7 = -5*(-2) + c

7 = 10 + c

c = 7-10 = -3

Now, we have the general equation of y = -5x -3 and we can use this to find a.

We'll treat a as x and y will be equal to 2:

2 = -5a -3

5 = -5a (Divide both sides by 5)

-a = 1 (now by -1)

a = -1

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3 years ago

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3 years ago

Read 2 more answers

PLEASE HELP!!!!<br> Which of these pair of functions are inverse functions?

Mamont248 [21]

Answer:

Option B and C are correct.

Step-by-step explanation:

Inverse function: If both the domain and the range are R for a function f(x), and if f(x) has an inverse g(x) then:

$f(g(x)) = g(f(x)) = x$ for every x∈R.

Let $f(x) = \frac{1}{2}(\ln(\frac{x}{2}) -1)$ and $g(x) = 2e^{2x+1}$

Use logarithmic rules:

$ln e^a = a$

$e^{lnx} = x$

$\ln a^b = b\ln a$

then, by definition;

$f(g(x)) = f(2e^{2x+1}) =\frac{1}{2}(\ln(\frac{2e^{2x+1}}{2})-1)$ = $\frac{1}{2}(\ln(e^{2x+1}}){-1) = \frac{1}{2} (2x+1-1) =\frac{1}{2}(2x) = x$

$g(f(x)) = g(\frac{1}{2}(\ln(\frac{x}{2}) -1)) = 2e^{2({\frac{1}{2}(\ln(\frac{x}{2}) -1})+1$ $2e^{(\ln(\frac{x}{2}) -1+1}=2e^{\ln(\frac{x}{2})} =2\cdot \frac{x}{2} = x$

Similarly;

for $f(x) = \frac{4 \ln(x^2)}{e^2}$ and $g(x) = e^{\frac{e^2 \cdot x}{8} }$

then, by definition;

$f(g(x)) = f(e^{\frac{e^2 \cdot x}{8}}) =\frac{4 \ln {(\frac{e^2 \cdot x}{8})^2}}{e^2}$ = $\frac{8 \ln {(\frac{e^2 \cdot x}{8})}}{e^2} =\frac{8\frac{e^2\cdot x}{8} }{e^2}=\frac{8e^2 \cdot x}{8e^2}=x$

Similarly,

g(f(x)) = x

Therefore, the only option B and C are correct. As the pairs of functions are inverse function.

3 0

3 years ago

Use the image below to answer the following parts.

12345 [234]

Answer:

Step-by-step explanation:

Part A

Since, the given angles are formed at a point are on a straight line, sum of these angles will be 180°.

Part B

(3x - 5)° + (4x + 2)° + (2x + 3)° = 180°

9x = 180

x = 20

Part C

m∠ADB = (3x - 5)°

= (3×20 - 5)°

= 55°

m∠DBK = (4x + 2)°

= (4×20 + 2)°

= 82°

m∠KBC = (2x + 3)°

= (2×20 + 3)°

= 43°

6 0

3 years ago