Answer:
2^11
Explanation:
Physical Memory Size = 32 KB = 32 x 2^10 B
Virtual Address space = 216 B
Page size is always equal to frame size.
Page size = 16 B. Therefore, Frame size = 16 B
If there is a restriction, the number of bits is calculated like this:
number of page entries = 2^[log2(physical memory size) - log2(n bit machine)]
where
physical memory size = 32KB which is the restriction
n bit machine = frame size = 16
Hence, we have page entries = 2^[log2(32*2^10) - log2(16)] = 2ˆ[15 - 4 ] = 2ˆ11
#accepting input from user
n=int(input("Enter a number: "))
#entered number is stored in a temporary variable
temp=n
#initializng required variables
rev=0
dgt=0
#digits are reversed inside while loop
while(n>0):
dgt=n%10
rev=rev*10+dgt
n=n//10
#original number and its reverse are compared
if(temp==rev):
#if equal, it's a palindrome
print("It is a Palindrome")
else:
#if not equal, it's not a palindrome
print("It is not a Palindrome")
#◌⑅⃝●♡⋆♡Nåmřāthā♡⋆♡●⑅◌
Answer:
The answer to this question is Yes it is possible
Explanation:
It can be done In the case where a special server is required in each network that would forward the request to the remote ARP(Address Resolution Protocol) server and will receive the response from the server and send it to the requesting host.So we conclude that we can do that hence the answer is Yes.
