To solve this problem you must apply the Intersecting Secant-Tangent Theorem. By definition, when a secant line and a tangent lline and a secant segment are drawn to a circle from an exterior point:

$(Tangent\ line)^2=(Secant\ line)(External\ Secant\ line)$

The total measure of the secant shown is:

$18+Diameter$

If the radius is 7, then the diameter is:

$D=7*2=14$

Therefore:

$Secant\ line=18+14=32$

You also know that:

$External\ Secant\ line=18\\Tangent\ line=x$

Keeping the above on mind, you can substitute values and solve for x:

$x^{2}=32*18$

$x=\sqrt{576}\\x=24$

4 0

3 years ago

A tour bus travels 2,160 miles in 36 hours. What is the average distance the bus travels in one hour?

Yuki888 [10]

60 miles because 2160 divided by 36 = 60

6 0

3 years ago

Read 2 more answers

Gia started to solve the equation 3(x − 10) − 5x = 2x − 26 below. They want to move the variables to the left side of the equati

LUCKY_DIMON [66]

Answer:

Subtract 2x from each side, Subtraction Property

Step-by-step explanation:

8 0

2 years ago

A growth medium is inoculated with 1,000 bacteria, which grow at a rate of 15% each day. What is the population of the culture 6

ddd [48]

Answer:

The population of bacteria after 6 days is 2,313.06

Step-by-step explanation:

Given as :

The initial population of bacteria = i = 1,000 bacteria

The growth rate of bacteria per day = 15%

Let The population of bacteria after 6 days = f

The time period of growth = 6 days

Now, According to question

The population of bacteria after 6 days = initial population × $(1+\dfrac{\textrm rate}{100})^{\textrm time}$

Or, f = i × $(1+\dfrac{\textrm r}{100})^{\textrm t}$

Or, f = 1000 × $(1+\dfrac{\textrm 15}{100})^{\textrm 6}$

Or, f = 1000 × $(1.15)^{6}$

Or, f = 1000 × 2.31306

∴ f = 2,313.06

So,The population of bacteria after 6 days = f = 2,313.06

Hence,The population of bacteria after 6 days is 2,313.06 Answer

3 0

3 years ago