First, you must know these formula d(e^f(x) = f'(x)e^x dx, e^a+b=e^a.e^b, and d(sinx) = cosxdx, secx = 1/ cosx
(secx)dy/dx=e^(y+sinx), implies <span>dy/dx=cosx .e^(y+sinx), and then
</span>dy=cosx .e^(y+sinx).dx, integdy=integ(cosx .e^(y+sinx).dx, equivalent of
integdy=integ(cosx .e^y.e^sinx)dx, integdy=e^y.integ.(cosx e^sinx)dx, but we know that d(e^sinx) =cosx e^sinx dx,
so integ.d(e^sinx) =integ.cosx e^sinx dx,
and e^sinx + C=integ.cosx e^sinxdx
finally, integdy=e^y.integ.(cosx e^sinx)dx=e^2. (e^sinx) +C
the answer is
y = e^2. (e^sinx) +C, you can check this answer to calculate dy/dx
Answer:
1. (3x - 2)(x + 5).
2. 2(x + 4)(x - 2).
3. (2x - 9)(2x + 9).
Step-by-step explanation:
1. f(x) = 3x^2 +13x -10
Try to factor by the ac method:
3 * -10 = -30
We need 2 numbers whose product is -30 and whose sum is + 13.
They are -2 and +15, so we write:
3x^2 + 15x - 2x - 10 Factor by grouping:
= 3x(x + 5) - 2(x + 5)
= (3x - 2)(x + 5).
2. f(x) = 2x^2+4x-16
= 2(x^2 + 2x - 8)
Now we need 2 numbers whose product is -8 and whose sum is + 2.
They are +4 and -2. So:
= 2(x + 4)(x - 2).
3. 4x^2 - 81 This is the difference of 2 squares so the factors are:
(2x - 9)(2x + 9).
Answer:
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Step-by-step explanation:
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I hope this helps you
1/8.20=2,5
4/5.3/8=12/40=0,3
1 1/8=9/8 9/8.1/9=1/8=0,125
3/4.1/3.2/5=1/10=0,1
