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Murljashka [212]

3 years ago

14

Y=2x-1 y=-3x+14 Solve for y

1 answer:

LUCKY_DIMON [66]3 years ago

3 0

Y=2x-1
y=-3x+14

First you would substitue one of the y's for the other so
2x-1=-3x+14

no you would solve for x...
add one on both sides
2x=-3x+15

now add 3x to both sides which becomes
5x=15

divide 5 on both sides which gives you x=3

now to solve for y plug into any one of the equations(doesn't matter which one) from before 3 for x and solve
y=2(3)-1
y=6-1
y=5

And that is you answer y=5

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Randy has two 28-pound blocks of ice for his snow cone stand. If each snow cone requires 2/3 pound of ice, how many snow cones c

irga5000 [103]

Answer:

The answer would be 28 divided by 2/3.

Step-by-step explanation:

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3 years ago

. Use the process outlined in the lesson to approximate the number 3√10. Use the approximation √10 ≈3162 277 7.

GaryK [48]

Answer:

sequence of five intervals

(1) 3³ < $3^{\sqrt{10} }$ < $3^{4}$

(2) $3^{3.1}$ < $3^{\sqrt{10} }$ < $3^{3.2}$

(3) $3^{3.16}$ < $3^{\sqrt{10} }$ < $3^{3.17}$

(4) $3^{3.162}$ < $3^{\sqrt{10} }$ < $3^{3.163}$

(5) $3^{3.1622}$ < $3^{\sqrt{10} }$ < $3^{3.1623}$

Step-by-step explanation:

as per question given data

√10 ≈ 3.162 277 7

to find out

sequence of five intervals

solution

as we have given that √10 value that is here

√10 ≈ 3.162 277 7 ........................1

so

when we find $3^{\sqrt{10} }$ ................2

put here √10 value in equation number 2

we get $3^{\sqrt{10} }$ that is 32.27

so

sequence of five intervals

(1) 3³ < $3^{\sqrt{10} }$ < $3^{4}$

(2) $3^{3.1}$ < $3^{\sqrt{10} }$ < $3^{3.2}$

(3) $3^{3.16}$ < $3^{\sqrt{10} }$ < $3^{3.17}$

(4) $3^{3.162}$ < $3^{\sqrt{10} }$ < $3^{3.163}$

(5) $3^{3.1622}$ < $3^{\sqrt{10} }$ < $3^{3.1623}$

5 0

3 years ago

A certain number line uses 20 spaces between consecutive integers.

noname [10]

Answer:

Distance between two consecutive tick marks is 0.05 units.

Step-by-step explanation:

We are given the following information in the question:

It is given that there are 20 ticks between two consecutive number.

Let n and n+1 be the consecutive number.

Formula:

Distance between two ticks =

$\displaystyle\frac{\text{Difeerence between the numbers}}{\text{Number of ticks}}\\\\= \frac{(n+1)-n}{20} = \frac{1}{20} = 0.05$

Thus, distance between two consecutive tick marks is 0.05 units.

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aliya0001 [1]

4 gallons

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prohojiy [21]

D is the answer
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